Which of the following is NOT valid Javascript code? a. let String myString = "Hello!"; b. const smallNum = 2n; c. a = 5; b = 6; var a, b; d. let a, b; a = 5; b = 6; e. const bigNum = 123456789012345678901234567890123456789012345678901234567890n; f. let myArray = [ null, undefined, "This", 4 ];

I know you guys are using AI. Don't you dare give me AI generated answer. This is warning ⚠️

Java Programming: Question 12 Not sure how to do this question. Help of any input and output would be appreciated.

X609: Magic Date A magic date is one when written in the following format, the month times the date equals the year e.g. 6/10/60. Write code that figures out if a user entered date is a magic date. The dates must be between 1 - 31, inclusive and the months between 1 - 12, inclusive. Let the user know whether they entered a magic date. If the input parameters are not valid, return false. Examples: magicDate(6, 10, 60) -> true magicDate(50, 12, 600) –> false

MONTY HALL LAB write this code in python and use # to answers questions - You are only allowed to use the following functions/methods: print(), range(), len(), sum(), max(), min(), and .append(). It is not mandatory to useall of these functions/methods. In this lab, you will write a code that simulates the Monty Hall Game Show. Thegame host gives the participant the choice of selecting one of three doors. Twodoors has a goat behind them and one door has a prize. The set of choices arerandomized each round. The participant needs to select the door with the prizebehind it. When the participant selects a door, the game host reveals a door with agoat behind it. The game host opens a door (different from the one selected by theparticipant) that has a goat behind it. The participant is then given the option tochange their choice. When you run your code, the code would display a message prompting the user toinput their door choice, labelled as 1, 2, and 3. Then the code will display a...

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:Equal #include <iostream>#include <cmath>using namespace std; int main() { double targetValue; double sensorReading; cin >> targetValue; cin >> sensorReading; if (/* Your solution goes here */) { cout << "Equal" << endl; } else { cout << "Not equal" << endl; } return 0;}