The solution must be recursive sumNRec: The method takes an integer array A and returns the sum of all integers in the parameter array

Part (1) Write a recursion method named CalculateSeries, that will receive one integer valuen as parameter. The method will calculate and return the term n in the following series: T(0)= 0 T(n)= 2 T(n-1) +1 Part (2) Write the main method to test your method. Enter n>> 5 T(5) = 31 %3D

1. Write a recursive method expFive(n) to compute y=5^n. For instance, if n is 0, y is 1. If n is 3, then y is 125. If n is 4, then y is 625. The recursive method cannot have loops. Then write a testing program to call the recursive method. If you run your program, the results should look like this:> run RecExpTest Enter a number: 3 125>run RecExpTest Enter a number: 3125 2. For two integers m and n, their GCD(Greatest Common Divisor) can be computed by a recursive function. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Once m is 0, the function returns n. Once n is 0, the function returns m. If neither is 0, the function can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n. Although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. Meaning your code needs to follow the given algorithm. Then...

The following recursive method get Number Equal searches the array x of 'n integers for occurrences of the integer val. It returns the number of integers in x that are equal to val. For example, if x contains the 9 integers 1, 2, 4, 4, 5, 6, 7, 8, and 9, then getNumberEqual(x, 9, 4) returns the value 2 because 4 occurs twice in x. public static int getNumberEqual(int x[], int n, int val) { if (n< 0) ( return 0; } else { if (x[n-1) == val) { return getNumberEqual(x, n-1, val) +1; } else { return getNumber Equal(x, n-1, val); } // end if ) // end if } // end get Number Equal Demonstrate that this method is recursive by listing the criteria of a recursive solution and stating how the method meets each criterion.

Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digit Sample Data : 453211145322224532714246813579 Sample Output : 23540

The following recursive method called z is created. This method accepts two parameters: A string s, and an integer index The code in the method is: if (index == s.length()) return ""; <------ base case if(index % 2 == 0) return ""+ s.charAt(index) + z(s,index+1); <---- recursive call else return z(s,index+1); <----- recursive call What would be the output with the call: z("javajavajava",0);

PYTHON: This exercise is a variation on "instrumenting" the recursive Fibonacci program to better understand its behavior. Write a supporting method that counts how many times the fib function is called to compute fib (n) where n is a user input. Hint: To solve this problem, you need an accumulator variable whose value "persists" between calls to fib. You can do this by making the count an instance variable of an object. Create a FibCounter class with the following methods: _init_(self) Creates a new FibCounter, setting its count instance variable to 0. getCount(self) Returns the value of count. fib(self, n) Recursive function to compute the nth Fibonacci number. It increments the count each time it is called. resetCount(self) Sets the count back to 0.