reate your own recursive void method that reverses its content of an array. Avoid creating a new array-reverese the contents of the current array. Here is the provided method header: public static void arrayReverse(int[] array

public class ArrayCommonOperations{ public static void main(String [] args) { //*** Task #1: Define and instantiate an array of integer numbers, with 10 elements //*** Task #2: Fill in the array with integer numbers from 1 to 100 //*** Task #3: define another array, named temp, and copy the initial array in it. //* This allows to preserve the original array //*** Task #4: Define the variables you need to calculate the following values, //* and initialize them with appropriate values. //*** Task #5: Print the original array //*** Task #6: Calculate the sum of all values //*** Task #7: Count the number of even values //*** Task #8: Calculate the minimum value in the array //*** Task #9: Calculate the maximum value in the array //*** Task #10: Replace the elements that are divisible by 3, with their value plus 2 //*** Task #11:...

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4. Remove all occurrences of a particular element from an array Consider an array named source. Write a method/function named removeAll( source, size, element) that removes all the occurrences of the given element in the source array. You must execute the method by passing an array, its size and the element to be removed. After calling the method, print the array to show whether all the occurrences of the element have been removed properly. nmm" Use Python Example: source=[10,2,30,2,50,2,2,60,0,0] removeAll(source,8,2) After calling removeAll(source,8,2), all the occurrences of 2 must be removed. Printing the array afterwards should give the output as: [ 10,30,50,60,0,0,0,0,0,0]

Refer to the following method that finds the smallest value in an array. /** Precondition: arr is initialized with int values. * Oparam arr the array to be processed Greturn the smallest value in arr public static int findMin(int[] arr) { int min = /* some value */; int index = 0; while (index < arr.length) { if (arr [index] < min) min = arr [index]; index++; } return min; } Which replacement(s) for /* some value */ will always result in correct execu- tion of the findMin method? I Integer.MIN_VALUE II Integer.MAX_VALUE III arr [0] (A) I only (B) II only (C) III only (D) I and III only (E) II and III only

Problem 1: Complete the sumOfDiagonals method in SumOfDiagonals.java to do the following: The method takes a 2D String array x as a parameter and returns no value. The method should calculate and print the sum of the elements on the major diagonal of the array x. In order to have a major diagonal, the array passed into the method should be a square (n-by-n), if it's not a square your program should handle that situation by throwing an exception. (Do Not worry about ragged arrays) If the array is a square, but there is a non-integer value on the major diagonal, your program should handle that situation by throwing an exception. When handling the exceptions, be as specific as you can be, (i.e. Do Not just use the Exception class to handle all exceptions in one catch block). Make the proper calls to the sumOfDiagonals method from the main method to test your sumOfDiagonals method on all the String arrays provided in the main method.

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Write java code that recursively calculates the Sum of the array cells. Program requirements: Create an array named MyArr and initialize it as follow: 19 27 81 243 88 1- Write a method named ArrSum that recursively calculates the Sum of the numbers in the Array and returns the Sum of the numbers. Hint: Method with 1 parameter (the Array) that returns 1 value (the Array's Sum). 2- Write a method named Display that displays the Array contents and Sum of the numbers. Hint: Method with 2 parameters (the Array) and Sum with no returns (void) 3- Your program output format must be the same as the following: =>> Array Summation Array: 31 19 27 81 243 88 100 6 10 5 Sum: 610 =>> End of the Program Documentation / Comments 31 100 6 10 5

Enhanced selection sort algorithm SelectionSortDemo.java package chapter7; /** This program demonstrates the selectionSort method in the ArrayTools class. */ public class SelectionSortDemo { public static void main(String[] arg) { int[] values = {5, 7, 2, 8, 9, 1}; // Display the unsorted array. System.out.println("The unsorted values are:"); for (int i = 0; i < values.length; i++) System.out.print(values[i] + " "); System.out.println(); // Sort the array. selectionSort(values); // Display the sorted array. System.out.println("The sorted values are:"); for (int i = 0; i < values.length; i++) System.out.print(values[i] + " "); System.out.println(); } /** The selectionSort method performs a selection sort on an int array. The array is sorted in ascending order. @param array The array to sort. */ public static void selectionSort(int[] array) { int startScan, index, minIndex, minValue; for (startScan = 0; startScan < (array.length-1); startScan++) { minIndex = startScan; minValue...

Method Details getCountInRange public static int getCountInRange​(int[] array, int lower, int upper) Returns the number of values in the range defined by lower (inclusive) and upper (inclusive) Parameters: array - integer array lower - lower limit upper - upper limit Returns: Number of values found Throws: java.lang.IllegalArgumentException - if array is null or lower is greater than upper Any error message is fine (e.g., "Invalid parameters(s)")

void changeAll(int x[]) { x[0] = x[0] + 5; return; The first element in an array would be increased by 5 The array would be the same because it was passed by value x would be increased by 5 All the elements in the passed array would be incremented by 5

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Wrist a code to find the iterative sum of an array and the range (max and min)