Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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void showArray ( int a[ ], int size ); // shows the array in the format "int a [ ] = { 3, 7, 4, ... ,5, 6, 3}
void showReverse ( int a[ ], int size ); // shows the array in reverse "int a [ ] = { 3, 6, 5, ... , 4, 7, 3 } "
int lowest ( int a[ ], int size ); // finds and returns the lowest value in the array (should be 3)
int highest ( int a[ ], int size ); // finds and returns the highest value in the array (should be 7)
int sumArray ( int a[ ], int size ); // calculates and returns the sum of all values in the array
float averageVal ( int a[ ], int size ); // calculates and returns the average of all values in the array
int count5 ( int a[ ], int size ); // returns how many times the number 5 appears in the array
int firstMinusLast ( int a[ ], int size ); // returns the difference b/w the First and Last Array Element
void showBeforeIndex( int a [ ], int index); // shows all array values before a specific index
void done ( );
Write the definitions of the functions with the given prototypes below. Function that return a value, must return it to the main, and then the value is shown from the main.
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- //Required Functionvoid func(int array_1[],int array_2[],int size){ for(int i=0;i<size;i++){ if(array_2[i]>array_1[i]){ array_1[i]=array_2[i]; } } return;} //main function to test the function.int main(){ int size=6; int a[]={1,5,9,8,7,6}; int b[]={1,4,10,12,7,15}; printf("First array before function call: "); for(int i=0;i<size;i++){ printf("%d ",a[i]); } func(a,b,size); //call to the created function printf("\nFirst array after function call: "); for(int i=0;i<size;i++){ printf("%d ",a[i]); } return 0;} 1. Write the statements to do the following: write a prototype for your function in the previous problem write a main function which includes the following steps declare two arrays of ints with 25 elements each prompt the user and read values into both arrays call your function from the previous problem print both arraysarrow_forward1. Array splitting in Java Create an integer array with 10 integer numbers, initialize the array arbitrarily but make sure there are both positive and negative integers. Then generate two arrays out of the original array, one array with all natural numbers (positive numbers or zeros) and another one with all negative numbers. Print out the number of elements and the detailed elements in each array.arrow_forwardProblem Description - JAVA PROGRAMMING Use a Two-dimensional (3x3) array to solve the following problem: Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive. Display the array after the user inputs each value. Rotate/flip the array by changing places. Make the rows columns and vice versa. You have to move the elements to their new locations. Remember to validate the input and display an error message if the user inputs invalid data. Documentation and the screenshot(s) of the results. Example: 1 2 3 4 5 6 7 8 9 the result will be : 1 4 7 2 5 8 3 6 9arrow_forward
- class Main { // this function will return the number elements in the given range public static int getCountInRange(int[] array, int lower, int upper) { int count = 0; // to count the numbers // this loop will count the numbers in the range for (int i = 0; i < array.length; i++) { // if element is in the range if (array[i] >= lower && array[i] <= upper) count++; } return count; } public static void main(String[] args) { // array int array[] = {1,2,3,4,5,6,7,8,9,0}; // ower and upper range int lower = 1, upper = 9; // throwing an exception...arrow_forwardpublic int binarySearch(int[]array, int num) {int low = 0;//low rangeint high = array.length -1; //high range int mid; //mid rangewhile () //while low is less than or equal to high{mid = ; //set middle range to be (low + high) /2if () { //if the array in the middle range = input number//return mid range }elseif () { //if the array in the middle range > input number//set the high value to be the mid value minus 1 }else{//set low value to be mid value plus one } }//return -1 here because that would mean that the number is not found in the loop}arrow_forwardvoid changeAll(int x[]) { x[0] = x[0] + 5; return; The first element in an array would be increased by 5 The array would be the same because it was passed by value x would be increased by 5 All the elements in the passed array would be incremented by 5arrow_forward
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