The first requirement: Using the SQL language, transform the following entity model into tables in the database.

student(sid, sname, sex, age, year, gpa) dept(dname, numphds) prof(pname, dname) course(cno, cname, dname) major(dname, sid) section(dname, cno, sectno, pname) enroll(sid, grade, dname, cno, sectno) Write the following SQL queries for the schema above: Print the course names, course numbers and section numbers of all classes with less than six students enrolled in them. Print the name(s) and sid(s) of the student(s) enrolled in the most classes. Print the names of departments that have one or more majors who are under 18 years old. Print the names and majors of students who are taking one of the College Geometry courses. For those departments that have no majors taking a College Geometry course, print the department name and the number of PhD students in the department. Print the names of students who are taking both a Computer Sciences course and a Mathematics course. For each department that has one or more majors with a GPA under 1.0, print the name of the...

Tables: t1- actor ( AID varchar(8), name varchar(30), salary numeric(8,2)) t2- movie ( MID varchar(8), title varchar(50)) primary key MID t3-actor_role (MID varchar(8), rolename varchar(20)) write queries in SQL to answer each of the following questions: (Table: actor movie actor_role) 1. Find the average salary of all actors. 2, Find the actor IAN's AID. 3. Find the names of all actors whose name includes the substring 'au'. 4. Find all actor's name who has had a role in movies (remove duplicates). 5. Find the MID of movie 'Life is Beautiful'.

SQL SUM Problem -SELECT * FROM [Sale Order] INNER JOIN Product ON [Sale Order] productID = Product.productID here i've joined two tables , now what i need to do is sum the productPrice of the rows with the same customerID .. order id and product id are the primary key

Task 2: The Driver Relationship team wants to arrange workshops and education materials to the drivers. However, the team wants to create clusters of the drivers based on their experience in InstantStay. To collect these detail, you will need to create a SQL function called DRIVER_STATUS to determine the level of the driver as follows: MASTER: more than 4 travels PRO: more than 2 travels ROOKIE: 2 or less travels In addition, run the function to verify it works as expected and send them back the driver levels. SQL Database Test: SELECT DRIVER_ID, DRIVER_STATUS(DRIVER_ID) FROM DRIVERS Create the DRIVER_STATUS function Expected Results: DRIVER_ID DRIVER_STATUS(DRIVER_ID) 2001 MASTER 2002 ROOKIE 2003 PRO 2004 ROOKIE 2005 ROOKIE

VINCE'S VINYL It is time to test Vince's database to see if it truly meets his needs. It is time to look back at the business rules and test them with some SQL. Look at the business rules you devel- oped previously, and design some SQL queries to test them. Documentation: Set up a test plan. List the rule, the SQL you wrote, and the results. Also note whether the database passes or fails the test. Your queries should include the following: Two or three simple SELECTS with various WHERE criteria. Two or three queries using aggregate functions. At least two queries that use joins. Two or three INSERT statements. One or two UPDATES and/or a DELETE.

SQL Query question

QUICK SQL REQUEST (beginner level...) Back at work on Monday morning, the Vice President of Purchasing asks you to help him with the analysis of in-process storage. He asks you to pull information regarding the number of products per storage location. The result of the query should show: - The name of the warehouse (Location) - The number of different products per storage location - The total quantity of products found at this storage location - The average price of all products found at this storage location He mentions that for the moment he is only interested in the locations that have more than 50 distinct products because he wants to start inventorying the biggest locations first. Show the locations in order of smallest to largest number of distinct products. My request is linked to the question but i'm having trouble executing it I would love to know how to do it, thanks in advance.

Execute a SQL statement to add a check constraint to the field mode_of_payment with values ('D', 'R' or 'C") in order_db

Database Q1: Select the correct SQL statement to provide the user Samer with read only permission on Employees table a) Grant read on Employee where username = Samer; b) Grant read only on Employee to Samer; c) Grant select to Samer on Employee; d) Grant select on Employee to Samer; Q2: Based on the TWO schema structures below, which SQL statement will create a view to show department names where each department has at least 5 employees? Employee (E_ID, E_Name, D_ID, E_Salary) Department (D_ID, D_Name, D_Address) (Select one) a) Create View Dept_Emp as select D_Name, count(E_ID) from Employee, Department where Employee D_ID = Department D_ID Group by D_Name Where count (E_ID) >= 5; b) Create View Dept_Emp as select D_Name, count(E_ID) from Employee D_ID = Department D_ID Group by D_Name Having count (E_ID) >= 5; c) Create View Dept_Emp as select D_Name, count(D_ID) from Employee, Department where Employee D_ID = Department D_ID Group by D_Name Having count (E_ID) >= 5; d)...

consider the following schema: Product(pid, name, type, manufacturer, price) Buys(cid, pid) Customer(cid, cname, age, gender) 1) write the following query in relational algebra; find the names of all customers who have purchased all products manufactured by sears. 2)write the following in sql: find the names of all the customers who have not purchased the most expensive product. 3) Write the following query in SQL. Find the names and cids of all customers who have purchased the second most expensive product. You can assume that no two products have the same prices.

True or False below: Given two relations named A and B, if we q-JOIN A and B, the maximum number of attributes in the result relation could be (the number of attributes of A) times(*) the number of attributes of B). * in an SQL SELECT statement means "all the tuples". In relational algebra, Cartesian Product (X) can be implemented using the q-JOIN operator. Cartesian Product ISA q-JOIN where q-condition always evaluates to true. SQL is based on Predicate Calculus. A query in SQL always specifies what should be included in the query result.

SQL DML/DDL There are five tables describing employees of a company, departments, buildings, which department(s) an employee works in (and a percentage of the time for each), and in which building an employee works (an employee may have more than one office). The primary key of each table is the attribute(s) in capitals and underlined. The foreign keys are in italics. Other attributes are not necessarily unique.Employee (EID, Ename, Salary, Start_Date, End_Date)Building (BID, Bname, Address)Department (DID, Dname, Annual_Budget)In_Department (EID, DID, Percentage_Time)In_Building (EID, BID)Write the SQL statements for the following.1. Find the names of Departments where NO employees work. 2. For employees who are still working in the company, end date has no value (empty). For those who have left the company and have end date values, show their names and the duration of their employment in years. 3. Find the names of buildings where more than 50 employees work. 4. The tables have...