Given two relations named A and B, if we q-JOIN A and B, the maximum number of attributes in the result relation could be (the number of attributes of A) times(*) the number of attributes of B). * in an SQL SELECT statement means "all the tuples". In relational algebra, Cartesian Product (X) can be implemented using the q-JOIN operator. Cartesian Product ISA q-JOIN where q-condition always evaluates to true. SQL is based on Predicate Calculus. A query in SQL always specifies what should be included in the query result.

SQL code for: (1) Hint: A NULL in the hours column should be considered as zero hours. Find the ssn, lname, and the total number of hours worked on projects for every employee whose total is less than 40 hours. Sort the result by lname */ /* (2) For every project that has more than 2 employees working on it: Find the project number, project name, number of employees working on it, and the total number of hours worked by all employees on that project. Sort the results by project number. /* (3) For every employee who has the highest salary in their department: Find the dno, ssn, lname, and salary. Sort the results by department number. */ /* (4) For every employee who does not work on any project that is located in Houston: Find the ssn and lname. Sort the results by lname /* (5) Hint: This is a DIVISION query For every employee who works on every project that is located in Stafford: Find the ssn and lname. Sort the results by lname */

Let's wa(k through a review of basic SQL syntax, using as an example the database that was mentionedearlier. This database has the following simple structure(* indicates a primary key):Courses: CourseID*, CourseName, TeacherIDTeachers: TeacherID*, TeacherNameStudents; StudentID*, StudentNameStudentCourses: CourseID*, StudentID*Using the above table, implement the following queries.Query 1: Student Enrollment Query 2: Teacher Class Size

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For below DEPARTMENT table write a SQL query so that repeated group names are shown with quotation symbol like in above desired output For understanding logic, can you give simple example in Microsoft SQL Server Management Studio 18. Thank you.

Intersection table is needed when you have a relationship 1:1 M:N M:1 1:M

Need help writing SQL statements for these, I'm having trouble with my returns. Explanation would help a lot.

Based on SQL query knowledge

Based on the following authorication commands (ordered from 1 to 4), which of the following privileges is true, assuming that Ali is the owner of the database? Order By Ali 1 2 3 4 Select one: Omar Ali Ali Command Grant Select on Employee to Omar with grant option; Grant Select on Employee to Samer with grant option; Grant Update on Employee to Omar with grant option; Revoke Select on Employee From Omar Cascade; a) Ali and Omar have Update privilege on employee Ali has select privilege on employee b) Ali and Omar have Update privilege on employee Omar and Samer have select privilege on employee elect c) Ali and Omar have Update privilege on employee Ali and Omar have select privilege on employee d) Ali and Omar have Update privilege on employee Ali, Omar and Samer have select privilege on employee

SQL Query Relational Algebra select avg(customer.age) as "avg_age" from AVG(avg_age) (customer) customer; 1. Select customer phone, customer.address, customer.fullname from customer where exists (select * from billing where billing.cid = customer. Customer id); 2. Select * from customer where customer.address in ('Ibri'); 3. Select billing.bill id from billing Group by bill id Having count (case when billing.b status = 'REJWCTED' then 1 end)>1; select * from customer order by full name, age;