In Kotlin, Write a higher-order function that takes two arguments and returns a String. The first argument is a String and the second is a function that takes a Char and returns a Boolean. Your function should return a String containing those of the characters in the original String for which the function returns true. Use a tail-recursive helper function. Remember to make sure you get the tail recursion right by using the tailrec annotation. Test the function

What is the return value of the function call Comp(4, 5), given the recursive function Comp defined below: int Comp(int a, int b) { if (a + b <= 6) return 3; else return Comp(a-1, b) + Comp(a, b-1); }

Using recursive functions in Python, given three letters in the alphabet, get their permutations together with the combinations of any two letters from it.

In kotlin, Write a recursive linear search function that takes a String and a Char and returns true if the String contains the Char. The base cases are that a) the length of the String is 0 or b) the first character in the String is the character we are searching for. then Modify the linear search function so that both the String and the Char are nullable. If either is null, return false.

Write a recursive function called Rev takes a string argument (str) and and integerargument(i – the initial string position). Rev prints the str in reverse. You may not useany built-in reverse function or method. You may use string’s length method.

Make a code using Recursion The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring("catwoman loves cats", "cat") would return 2 countSubstring("aaa nice", "aa") would return 1 because "aa" only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) {...

Write a program called p3.py that contains a function called reveal_recursive() that takes a word (string) and the length of the word (int) as input and has the following functionality: 1. prints the word where all characters are replaced by underscores 2. continue to print the word revealing one character at a time. i.e., the second line printed should print the first character followed by "_"’s representing the rest of the word. (see example below) 3. the function should end after printing the entire word once. 4. This function should be recursive Example: #the word is kangaroo ________ k_______ ka______ kan_____ kang____ kanga___ kangar__ kangaro_ kangaroo

The 4th problem mimics the situation where eagles flying in the sky can be spotted and counted.FindEagles: a recursive function that examines and counts the number of objects (eagles) in aphotograph. The data is in a two-dimensional grid of cells, each of which may be empty (value 0) orfilled (value 1 to 9). Maximum grid size is 50 x 50. The filled cells that are connected form an object(eagle). Two cells are connected if they are vertically, horizontally, or diagonally adjacent. Thefollowing figure shows 3 x 4 grids with 3 eagles. 0 0 1 21 0 0 01 0 3 1 FindEagle function takes as parameters the 2-D array and the x-y coordinates of a cell that is a part ofan eagle (non-zero value) and erases (change to 0) the image of an eagle. The function FindEagleshould return an integer value that counts how many cells has been counted as part of an eagle and havebeen erased. The following sample data has two pictures, the first one is 3 x 4, and the second one is 5 x 5 grids. Notethat your program...

Need some help with this c++ problem In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 211 and you know that 210 = 1024, then 211 =わ 2 ×ばつかける 1024 =わ 2048. Based on this observation, write a recursive function int pow2(int n) where n is the exponent. If the exponent is negative, return -1. int pow2(int n) { ..... }

Please answer quick in python

DO NOT COPY ANSWER FROM ANOTHER QUESTION LEAVE IF you cannot do it perfectly. Otherwise, I will not only DOWN the vote but also REPORT you to the official Chegg team.I won't stop calling Chegg until they really pay attention to this trash behavior. Write a structurally recursive function (prefix->postfix exp) that takes as input an expression in the same little language as Problem 4. prefix->postfix returns an expression of the same form as its input, except that all function applications have been reversed. Finish this Racket code below to answer the question above.(define prefix->postfix(lambda (exp)))

‘Write a function nesting(), which takes an arbitrary number of parameters, and returns a list containing the arguments. Write another function unnesting(), which takes a list L as the parameter and retums a 1D list. Notice that, you should be able to use loops to solve thisproblem and should not use recursive functions (which we will not cover in this course). ‘Write assertions to test the two functions.For example nesting(1, nesting(2, 3, nesting(4, 5, [6])), [7, 8], 9)unnesting([1, [2, 3, [4, 5, [6]]], [7. 8], 9]) (1, [2, 3, [4, 5, [6]]], [7, 8], 9][1, 2,3, 4, 5, 6, 7, 8 9]

e. Problem 5. Devise a function that receives a string and computes how many asterisks are in the string with a recursive method. For instance, if the input is "Able was I ere ***Elba", the function should output 3. If the input is "Peanuts", the function should return 0. Approach: Let's assume the signature of our function is countAsterisks(s) where s is the input string. In the body of your function, check if s[0] is equal to an asterisk. If the string contains only a single character and it is an asterisk, return 1. If the string contains only a single character and it is not an asterisk, return 0. If the string is longer than one character, determine if the first character is an asterisk and count it if this is the case. Then, create a new string s1 that is the same as the input string s but without the first character. Recursively call countAsterisks (s1) and return the value returned from this recursive call, plus one (if there is an asterisk in s[0]). Also, writing any explicit...