Write a function that outputs a string passed into the function in reverse. Use recursion to achieve this.

Please explain what the recursive function will do. This function takes a stringargument (str), and two integer arguments: i – the first position in the string; and x – thelast position in the string. Please show output and recursive trace of Mystery("abbba", 0, 4), Mystery ("acca", 0, 3), Mystery ("abcd", 0, 3) Public Static boolean Mystery(string str, int i, int x)[ if(i >= x) return true; else if(str[i] != str[x]) return false; else return Mystery (str, i+1, x-1); }

Use ONLY PyCharm, please.Thank you.

Using recursive functions in Python, given three letters in the alphabet, get their permutations together with the combinations of any two letters from it.

Write a recursive function diff (java) which utilizes two positive integer arguments (x and y) and returns |x – y|. An x - y calculation may not be performed during the function. Thanks so much for your help!

An arithmetic sequence starts 2, 5, . . . Write a recursive definition for this sequence using function notation.

Write a recursive function called Rev takes a string argument (str) and and integerargument(i – the initial string position). Rev prints the str in reverse. You may not useany built-in reverse function or method. You may use string’s length method.

Make a code using Recursion The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring("catwoman loves cats", "cat") would return 2 countSubstring("aaa nice", "aa") would return 1 because "aa" only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) {...

Write a recursive function to see if the first letter matches the last letter, return the middle letters and check until only 0 or 1 letters are left. It returns True or False. Here is the original code that needs to be checked: # Returns the first character of the string str def firstCharacter(str): return str[:1] # Returns the last character of a string str def lastCharacter(str): return str[-1:] # Returns the string that results from removing the first # and last characters from str def middleCharacters(str): return str[1:-1] def isPalindrome(str): # base case #1 # base case #2 # recursive case pass Python code

Write a recursive function (Java) called Fac which takes one positive integer argument (n) and returns n! You may not use a built-in factorial method or function.

The 4th problem mimics the situation where eagles flying in the sky can be spotted and counted.FindEagles: a recursive function that examines and counts the number of objects (eagles) in aphotograph. The data is in a two-dimensional grid of cells, each of which may be empty (value 0) orfilled (value 1 to 9). Maximum grid size is 50 x 50. The filled cells that are connected form an object(eagle). Two cells are connected if they are vertically, horizontally, or diagonally adjacent. Thefollowing figure shows 3 x 4 grids with 3 eagles. 0 0 1 21 0 0 01 0 3 1 FindEagle function takes as parameters the 2-D array and the x-y coordinates of a cell that is a part ofan eagle (non-zero value) and erases (change to 0) the image of an eagle. The function FindEagleshould return an integer value that counts how many cells has been counted as part of an eagle and havebeen erased. The following sample data has two pictures, the first one is 3 x 4, and the second one is 5 x 5 grids. Notethat your program...

For this exercise, you are going to write a recursive function that counts down to a Blastoff! Your recursive function will not actually print. It will return a String that can be printed from the main function. Each recursive call will add on to that string. In your main function, prompt the user for a starting value, then print the results. Sample Output Please enter a number to start: 5 5 4 3 2 1 Blastoff! import java.util.Scanner; public class Countdown{public static void main(String[] args){// Start here}public static String countdown(int number){// Base case - return Blastoff!// Recursive call}}

Need some help with this c++ recursive function: Write the function int countEights(int n). Inside the function, compute recursively (no loops) the count of the occurrences of 8 as a digit inside the parameter n. Except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). Here are some examples: countEights(8) returns 1 countEights(818 returns 2 countEights(8818) returns 4