cursive implementation of Euclid's Algorith for finding the greatest common divisor (GCD) of two intergers. Descriptions of this algorithm are available in algebra books and on the web. (Note: A nonrecursive version

need help with R2

Need python help. For problems 1 and 2, add your code to the file Lab2.java. Add your tests in the main function of Lab2.java. Do not use static variables in class Lab2 to implement recursive methods. Problem 1: Implement a recursive method min that accepts an array and returns the minimum element in the array. The recursive step should divide the array into two halves and find the minimum in each half. The program should run in O(n) time and consume O(logn) memory. Demonstrate the output of min on the array int [] a = { 2, 3, 5, 7, 11, 13, 17, 19, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 23, 29, 31, 37, 41, 43 } Problem 2 You have been offered a job that pays as follows: On the first day, you are paid 1 cent, on the second day, 2 cents, on the third day, 4 cents and so on. In other words, your pay doubles every day. Write a recursive method computePay that for a given day number computes the pay in cents. Assume that you accumulate all the money that you are paid. Write a...

Write a recursive solution to the problem below. You MUST use only one method, and that method must have the provided method header. You are allowed to use loops, but you must also use recursion. Given a word of length n, print every possible word of length n that can be made with those characters. Note: The order of the output does not matter, only that all possibilities are listed. Example: Input: rot Output: rot, rto, otr, ort, tro, tor Input: frog Output: frog, frgo, fogr, forg, fgro, fgor, rogf, rofg, rgfo, rgof, rfog, rfgo, ogfr, ogrf, ofrg, ofgr, orgf, orfg, gfro, gfor, grof, grfo, gofr, gorf public void printAllPossibilities (String prefix, String suffix){ }

I am working on this recursive function, and I am drawing a blank. Line 15 else if(s.charAt(0) != s.length () -1 && ............ )) Is there a String method that looks for intergers ? Suppose to look to see if it is the last value and if it is a Integer, if it is , add the vaules that intergers together for a total sum public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be in the same class and have the following signatures. //use the if/else statement , Find the base case and -1 till you get to base case //recursive function that adds up the digits in the String public static int sumIt(String s) { int sumOfNumbers =0; //if String length is less or equal to 1 retrun 1. for (int i = 0; i >= 0 ;i++) if (s.length()<= 1)//Base case = 1 return 1; //else if the CharAt(value in index at 0 = 1) is not equal to the last vaule in the string else if(s.charAt(0) != s.length ()...

Write a recursive method that returns the value of N! (N factorial) using the definition given in this chapter. Explain why you would not normally use recursion to solve this problem.

Make a code using Recursion The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring("catwoman loves cats", "cat") would return 2 countSubstring("aaa nice", "aa") would return 1 because "aa" only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) {...

Write and test a Java/Python recursive method for finding the minimum element in an array, A, of n elements. What the running time? Hint: an array of size 1 would be the stop condition. The implementation is similar to linearSum method in lecture 5 examples. You can use the Math.min method for finding the minimum of two numbers.

Determine whether a string is a palindromeA palindrome is a string of characters that reads the same from right to left as it does from left to right, regardless of punctuation and spaces.The specifications for this assignment are: •Write and test a non-recursive solution in Java that determines whether a string is a palindrome •Your program should consist of at least two methods: (1) the main method (2) the method which performs the task of determining whether the specified string is a palindrome. You should name this method isPalindrome. You should name the class that contains your "main" method and the isPalindrome method FindPalindrome. •You must use a Stack and a Queue in your solution: Write your own Stack and Queue based on the Vector in the Java API and use those in your solution. You should name those classes StackVector and QueueVector respectively. You already have access to the relevant exception classes and interfaces for the above ADTs. •All of your belong to a Java...

Consider a recursive function, called f, that computes powers of 3 using only the + operator. Assume n> = 0. int f(int n) { if (n == 0) return 1; return f(n-1) + f(n-1) + f(n-1); } Give an optimized version of f, called g, where we save the result of the recursive call to a temporary variable t, then return t+t+t. i got int g(int n) { if (n == 0) return 1; int t = g(n - 1); return t+t+t; } so now Write a recurrence relation for T(n), the number addition operations performed by g(n) in terms of n.

The following recursive method get Number Equal searches the array x of 'n integers for occurrences of the integer val. It returns the number of integers in x that are equal to val. For example, if x contains the 9 integers 1, 2, 4, 4, 5, 6, 7, 8, and 9, then getNumberEqual(x, 9, 4) returns the value 2 because 4 occurs twice in x. public static int getNumberEqual(int x[], int n, int val) { if (n< 0) ( return 0; } else { if (x[n-1) == val) { return getNumberEqual(x, n-1, val) +1; } else { return getNumber Equal(x, n-1, val); } // end if ) // end if } // end get Number Equal Demonstrate that this method is recursive by listing the criteria of a recursive solution and stating how the method meets each criterion.

Please do it using recursive approch. Recently | asked the same question, but i get in iterative approch. So please take mind on that. Write a java program to find the LCM of two user entered integer numbers.

Give a recursive definition for the set of all strings of a’s and b’s that begins with an a and ends in a b. Say, S = { ab, aab, abb, aaab, aabb, abbb, abab..} Let S be the set of all strings of a’s and b’s that begins with a and ends in a b. The recursive definition is as follows – Base:... Recursion: If u ∈ S, then... Restriction: There are no elements of S other than those obtained from the base and recursion of S.