Loop through an array in jQuery

Question

How can I loop through this $user array in jQuery? If 'Failure' returned then error should be printed.

Solution here actually prints it but with this output which is wrong: undefinedadmin_1,admin_2,admin_3

Thanks in advance

<?php
$id = $_POST['id'];
if($id == 1)
{
 $users['data'] = array(array('name'=> 'admin_1'), array('name'=> 'admin_2'), array('name'=> 'admin_2'));
 echo json_encode($users);
}
else
{
 $users['data'] = 'Failure';
 echo json_encode($users);
}
?>
$.ajax({
 type : 'POST',
 url : 'list.php',
 data : 'id=' + text_id,
 dataType : 'json',
 success : function(response)
 {
 //IF not 'Failure', loop through the array and print content into div.success
 //IF 'Failure', show div.fail
 }
});

Answer 1

if(response.data == 'Failure') {
 console.log('error');
 return false;
}
for(var i = 0; i < response.data.length; i++) {
 if(typeof response.data[i].name != 'undefined') {
 console.log(response.data[i].name);
 }
}

• BentCoder: I have to store names in a variable and print it afterwards but result = result+response.data[i].name + ', '; prints it like this: undefinedadmin_1,admin_2,admin_3

Answer 2

if ($.isArray(response)) {
 //loop through array
} else {
 //show error
}