VS Code snippet - how to get the relative_filepath without the file extension

Question

How can I get the relative_filepath without the extension and backslash change ?

I found two transforms:

1. "${RELATIVE_FILEPATH/[\\]/\//g/}"
2. "${RELATIVE_FILEPATH/(.js)//}"

If the relative file path is \aaa\bbb\ccc.js

I tried this:

/${RELATIVE_FILEPATH/((.js))}|/[\\]/${1://}${2://g/}/}

I want to get text like this: /aaa/bbb/ccc

Thank you.

• 이병옥: thank for correct words.

Answer 1

Try this snippet:

"Remove extension and swap to forward slash": {
 "prefix": "t2",
 "body": [
 // "${RELATIVE_FILEPATH}",
 "/${RELATIVE_FILEPATH/.js|(\\\\)/${1:+\/}/g}",
 ],
 "description": ""
},

Note the double escapes in .js|(\\\\) are necessary.
And I added the + to the ${1:+\/}.

• 이병옥: thank you for your help. Thanks to you you saved me time. Your code works correctly. ^^