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There have been a couple of questions (e.g. this and this) asking whether every monad in Haskell (other than IO) has a corresponding monad transformer. Now I would like to ask a complementary question. Does every monad have exactly one transformer (or none as in the case of IO) or can it have more than one transformer?

A counterexample would be two monad transformers that would produce monads behaving identically when applied to the identity monad would but would produce differently behaving monads when applied to some other monad. If the answer is that a monad can have more than one transformer I would like to have a Haskell example which is as simple as possible. These don't have to be actually useful transformers (though that would be interesting).

Some of the answers in the linked question seemed to suggest that a monad could have more than one transformer. However, I don't know much category theory beyond the basic definition of a category so I wasn't sure whether they are an answer to this question.

asked Jun 3, 2022 at 13:48
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    At some point I found myself needing a simple transformer I called OuterMaybeT, which is different from MaybeT in general yet does give OuterMaybeT Identity ≌ Maybe. But only for applicative, I don't think it can be used as a monad transformer, and I actually never checked whether it's even law-abiding. Commented Jun 3, 2022 at 14:23
  • @leftaroundabout OuterMaybe f is just Compose Maybe f, isn't it? So it should be law-abiding as far as I can see. Commented Jun 3, 2022 at 16:11
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    I mean we can trivially define a type T for which T Identity ~= Maybe and T [] ~= [], right? So... no, they're not unique. It's sort of a degenerate example, but then I can't really think of a clear property that would formalize my intuition about what I consider degenerate and what I don't. Maybe some sort of type-level analogue of parametricity or something...? Commented Jun 3, 2022 at 16:23
  • @DanielWagner Do you mean that one would give two separate instance declarations for T Identity and T []? Of course then (if that's what you meant) one could define each however one wishes. However, that feels more like two separate transformers than one transformer (as an alternative to MaybeT). I think what would be sufficient for a "non-degenerate" case is for the transformer to have one declaration of the form instance (Monad m) => Monad (T m) where. Not sure if this is asking too much. I have so far only skimmed the answers but I think I'll be wiser after reading them with care. Commented Jun 6, 2022 at 0:08
  • @QuantumWiz With the technique I'm thinking of (GADTs), it would be possible to write just a single instance. Commented Jun 6, 2022 at 1:02

3 Answers 3

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Here's one idea for a counterexample to uniqueness. We know that in general, monads don't compose... but we also know that if there's an appropriate swap operation, you can compose them[1]! Let's make a class for monads that can swap with themselves.

-- | laws (from [1]):
-- swap . fmap (fmap f) = fmap (fmap f) . swap
-- swap . pure = fmap pure
-- swap . fmap pure = pure
-- fmap join . swap . fmap (join . fmap swap) = join . fmap swap . fmap join . swap
class Monad m => Swap m where
 swap :: m (m a) -> m (m a)
instance Swap Identity where swap = id
instance Swap Maybe where
 swap Nothing = Just Nothing
 swap (Just Nothing) = Nothing
 swap (Just (Just x)) = Just (Just x)

Then we can build a monad transformer that composes a monad with itself, like so:

newtype Twice m a = Twice (m (m a))

Hopefully it should be obvious what pure and (<$>) do. Rather than defining (>>=), I'll define join, as I think it's a bit more obvious what's going on; (>>=) can be derived from it.

instance Swap m => Monad (Twice m) where
 join = id
 . Twice -- rewrap newtype
 . fmap join . join . fmap swap -- from [1]
 . runTwice . fmap runTwice -- unwrap newtype
instance MonadTrans Twice where lift = Twice . pure

I haven't checked that lift obeys the MonadTrans laws for all Swap instances, but I did check them for Identity and Maybe.

Now, we have

IdentityT Identity ~= Identity ~= Twice Identity
IdentityT Maybe ~= Maybe !~= Twice Maybe

which shows that IdentityT is not a unique monad transformer for producing Identity.

[1] Composing monads by Mark P. Jones and Luc Duponcheel

answered Jun 3, 2022 at 18:09
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8 Comments

But here, the monad transformer is Twice ? Isn't it ? And you provide a single definition of Twice. Am I wrong ? I mean you can say that Swap is also a monad transformer but you did not provide the lift function.
I think I misread your text. IdentityT and Twice are the monad transformers. So I will look at it.
What's the definition of return? Is it Twice . return . return or did I misunderstand?
@QuantumWiz You understood.
Twice is not a correct monad transformer because Twice cannot be applied to an arbitrary monad m, only to certain monads that have swap. A monad transformer t should produce a new lawful monad t m for any monad m, not just for a subset of monads.
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The identity monad has at least two monad transformers: the identity monad transformer and the codensity monad transformer.

newtype IdentityT m a = IdentityT (m a)
newtype Codensity m a = Codensity (forall r. (a -> m r) -> m r)

Indeed, considering Codensity Identity, forall r. (a -> r) -> r is isomorphic to a.

These monad transformers are quite different. One example is that "bracket" can be defined as a monadic action in Codensity:

bracket :: Monad m => m () -> m () -> Codensity m ()
bracket before after = Codensity (\k -> before *> k () *> after)

whereas transposing that signature to IdentityT doesn't make much sense

bracket :: Monad m => m () -> m () -> IdentityT m () -- cannot implement the same functionality

Other examples can be found similarly from variants of the continuation/codensity monad, though I don't see a general scheme yet.

The state monad corresponds to the state monad transformer and to the composition of Codensity and ReaderT:

newtype StateT s m a = StateT (s -> m (s, a))
newtype CStateT s m a = CStateT (Codensity (ReaderT s m) a)

The list monad corresponds to at least three monad transformers, not including the wrong one:

newtype ListT m a = ListT (m (Maybe (a, ListT m a))) -- list-t
newtype LogicT m a = LogicT (forall r. (a -> m r -> m r) -> m r -> m r) -- logict
newtype MContT m a = MContT (forall r. Monoid r => (a -> m r) -> m r))

The first two can be found respectively in the packages list-t (also in an equivalent form in pipes), and logict.

answered Jun 3, 2022 at 19:36

8 Comments

Do I understand correctly that Codensity is both a monad transformer and also a monad in the sense that it doesn't have to be applied to another monad to be an instance of Monad?
No it's only a monad transformer.
Codensity is to monads as difference lists are to lists. See also Notions of computation as monoids.
@Li-yaoXia What about the type newtype LT m a = LT (forall r. (a -> m (r -> r)) -> m (r -> r))? Is this yet another transformer for the List monad? This is a more straightforward application of the codensity monad's transformer.
Yeah, that's another example. It looks quite close to MContT, since the only thing you can do with (r -> r) functions is to compose them or form the identity.
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There is another example of a monad that has two inequivalent transformers: the "selection" monad.

 type Sel r a = (a -> r) -> a

The monad is not well known but there are papers that mention it. Here is a package that refers to some papers:

https://hackage.haskell.org/package/transformers-0.6.0.4/docs/Control-Monad-Trans-Select.html

That package implements one transformer:

type SelT r m a = (a -> m r) -> m a

But there exists a second transformer:

type Sel2T r m a = (m a -> r ) -> m a

Proving laws for this transformer is more difficult but I have done it.

An advantage of the second transformer is that it is covariant in m, so the hoist function can be defined:

 hoist :: (m a -> n a) -> Sel2T r m a -> Sel2T r n a

The second transformer is "fully featured", has all lifts and "hoist". The first transformer is not fully featured; for example, you cannot define blift :: Sel r a -> SelT r m a. In other words, you cannot embed monadic computations from Sel into SelT, just like you can't do that with the Continuation monad and the Codensity monad.

But with the Sel2T transformer, all lifts exist and you can embed Sel computations into Sel2T.

This example shows a monad with two transformers without using the Codensity construction in any way.

answered Oct 1, 2022 at 16:54

2 Comments

Is there a short intuitive explanation of what the selection monad does?
@QuantumWiz It returns a value of type a given a "selection criterion" expressed by a function of type a-> r. In the simplest nontrivial case, take r = Boolean and so a function of type a -> r is just a predicate saying whether a given value of type a is "good" or "bad". A selection function of type (a -> Boolean) -> a will somehow return some value of type a given such a predicate.

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