vscode snippet transform file name regex

Question

I'm trying to transform file-name.dto.ts to FileName in a snippet.

${TM_FILENAME_BASE/^(.*)([^.*]).*/${1:/pascalcase}2ドル/}

However, I'm not quite sure how to transform the second capture group or third.

If we don't wrap with a parenthesis, does it mean we don't capture?

 export class ${TM_FILENAME_BASE/^(.)([^.]*).*/${1:/upcase}2ドル/}Input {2ドル},
 export class ${TM_FILENAME_BASE/^(.*).*/${1:/pascalcase}2ドル/}Output {},

• Mark: I am not clear on what output you want on the Output line? The same thing, just export class FileNameOutput {}?

Answer 1

For the first line (the Input line), try this:

"export class ${TM_FILENAME_BASE/^([^-]*)-([^.]*).*/${1:/pascalcase}${2:/pascalcase}/}Input {2ドル},"

1. ${TM_FILENAME_BASE} alone gets you tofile-name.dto

2. Capture group 1 ^([^-]*) gets you the part before the first -

3. Match the - but you will ignore it in the output so it doesn't need to be in a capture group.

4. Capture group 2 ([^.]*) after the - until the first .

5. The rest .* will match .dto which again will be ignored so it doesn't need to be a capture group, but must be matched - you will effectively replace it with nothing.

Replacing with the transform: ${1:/pascalcase}${2:/pascalcase} so the first letter of both capture groups will be capitalized, the rest lower case.

On the Output line, if you are looking for this result:

export class FileNameOutput {}

use

"export class ${TM_FILENAME_BASE/^([^-]*)-([^.]*).*/${1:/pascalcase}${2:/pascalcase}/}Output {},"

---

Just in case you don't realize it, in your code:

export class ${TM_FILENAME_BASE/^(.)([^.]*).*/${1:/upcase}2ドル/}Input {2ドル},

that last {2ドル} is NOT referring to any capture group - it is outside any transform. It is only referring to a tabstop - where your cursor will go. Let me know if it is your intention that that final {2ドル} actually be a transformed capture group.

• Allen Kim: Thank you so much. I now completely understood how it is working :)