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I have a repo that looks like this

dev ---> common ---> utils.py
 ---> scripts --> upload_to_blob.py

It gives following error when I try to import utils from common

Traceback (most recent call last):
 File "scheduled_scripts/upload_to_blob.py", line 6, in <module>
 from common import utils
ModuleNotFoundError: No module named 'common'

I am using Python 3.6 env in Anaconda with base Python 2.7

asked Aug 10, 2020 at 5:54
1
  • plz show us the code that use another file Commented Aug 10, 2020 at 6:00

2 Answers 2

1

Have __init__.py files in your directories and you can access the other files.

dev -
 |- common 
 | |- utils.py
 | |- __init__.py
 |- scripts
 | |- upload_to_blob.py
 | |- __init__.py
 |- __init__.py

if you want to include from the file, you can use like below

from common.utils import *
answered Aug 10, 2020 at 6:16
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Comments

1

By default, you cannot. When importing a file, Python only searches the current directory, the directory the entry point script runs from, and sys.path which includes locations like the package installation directory (it's actually a little more complicated than that, but that covers most cases).

However, you can add to the Python path at runtime:

# some_file.py
import sys
# insert at 1, 0 is the script path (or '' in REPL)
sys.path.insert(1, 'scheduled_scripts/upload_to_blob.py')
import file
answered Aug 10, 2020 at 5:59

2 Comments

What would this refer to '/path/to/application/app/folder' ? which folder?
still same issue

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