How to get the URL without any parameters in JavaScript?

Question

If I use:

alert(window.location.href);

I get everything including query strings. Is there a way to just get the main url part, for example:

http://mysite.com/somedir/somefile/

instead of

http://mysite.com/somedir/somefile/?foo=bar&loo=goo

• Alex Angas: possible duplicate of Remove querystring from URL

Answer 1

This is possible, but you'll have to build it manually from the location object:

location.origin + location.pathname

• JonnyReeves: Note that you don't need to supply the location.protocol as all modern browsers (including IE6) will automatically inherit the current protocol. ie: '//' + location.host + location.pathname
• lonesomeday: @JonnyReeves If you're using it in the current document, that's true: good point. There are occasions when it might be necessary, e.g. if outputting the URL as plain text.
• izogfif: It's missing port, so this will return incorrect result for page http://www.example.com:8080/asdf.html?foo=bar
• Coderer: You can save a few characters with location.origin, which I believe also addresses @izogfif's concern.
• Air: @izogfif (really old post I know) You said this solution is missing port, but I don't believe it is. location.hostname returns the host name without the port, location.host should return the complete host value (port included). Just so others are aware of the difference between the two.

Answer 2

Every answer is rather convoluted. Here:

var url = window.location.href.split('?')[0];

Even if a ? isn't present, it'll still return the first argument, which will be your full URL, minus query string.

It's also protocol-agnostic, meaning you could even use it for things like ftp, itunes.etc.

• Bahattin Ungormus: in case you need to remove the anchors window.location.href.split(/[?#]/)[0];
• mehmet: indeed every answer is rather convoluted
• Oddman: @mehmet all ears if you have a simpler approach :)
• mehmet: @Oddman, I absolutely don't remember what I was thinking then, but I guess that might be an affirmative statement :))
• Oddman: @Vishal--JAVA--CQ "better" is subjective, but it's simpler.

Answer 3

I'm LATE to the party, but I had to solve this recently, figured I'd share the wealth.

const url = window.location.origin + window.location.pathname
//http://example.com/somedir/somefile/

window.location.origin will give you the base url, in our test case: http://example.com

window.location.pathname will give you the route path (after the base url), in our test case /somedir/somefile

SOLUTION 2

You can simply do the following to get rid of the query parameters.

const url = window.location.href.split('?')[0]

• Arash: Solution 2 is not complete and will include the hashes (#) if come before the QSPs.

Answer 4

Use the URL() constructor, then extract and concatenate the origin and pathname. This will automatically strip the search (aka query) parameters from the url, leaving the scheme, domain, port and pathname only.

const url = new URL('http://example.com/somedir/?foo=bar');
console.log(url.origin + url.pathname);

As a note, this type of transformation is usually referred to as normalization, specifically in this case URI Normalization. There may already exist libraries that accomplish this more robustly with more options in your environment.

Answer 5

Use indexOf

var url = "http://mysite.com/somedir/somefile/?aa";
if (url.indexOf("?")>-1){
url = url.substr(0,url.indexOf("?"));
}

• gouessej: It doesn't remove #.

Answer 6

You can concat origin and pathname, if theres present a port such as example.com:80, that will be included as well.

location.origin + location.pathname

• gouessej: This solution doesn't work with Microsoft Internet Explorer <= 10: developer.mozilla.org/en-US/docs/Web/API/Location/origin

Answer 7

Just one more alternative using URL

var theUrl = new URL(window.location.href);
theUrl.search = ""; //Remove any params
theUrl //as URL object
theUrl.href //as a string

Answer 8

You can use a regular expression: window.location.href.match(/^[^\#\?]+/)[0]

Answer 9

var url = "tp://mysite.com/somedir/somefile/?foo=bar&loo=goo" 
url.substring(0,url.indexOf("?"));

• actimel: This presumes, that parameter is defined. Much better is url.split('?')[0]

Answer 10

You can do this

window.location.origin + window.location.pathname

Answer 11

If you look at the documentation you can take just the properties you're interested in from the window object i.e.

protocol + '//' + hostname + pathname

• gouessej: You lose the port number with your suggestion, lonesomeday's solution is better in my humble opinion.