using math.random method to create dice method

Question

ı basically created a program for a bet game and ı wanted to use math.random method to obtain possible face values.

my question is that math.random is always same value so ı cannot use it repeatedly.

how can ı use math.random method repeatedly. ı dont want to get same value for my dice;

import java.util.Scanner;
public class Lab06d
{
 public static double money(double userMoney, int option, double bet )
 {
 //variable
 int dice1;
 int dice2;
 //codes
 dice1 = (int) Math.random() * 6 + 1;
 dice2 = (int) Math.random() * 6 + 1;
 System.out.println("dice sum: " + dice1 + dice2 );
 if(option == 1)
 {
 if((dice1 + dice2) % 2 == 1)
 userMoney = userMoney + ( bet / 2); 
 else
 userMoney = userMoney - ( bet / 4);
 }
 if(option == 2)
 {
 if((dice1 + dice2) % 2 == 1)
 userMoney = userMoney - ( bet / 4); 
 else
 userMoney = userMoney + ( bet / 2);
 }
 if(option == 3)
 {
 if((dice1 == 1 && dice1 == 1) || (dice1 == 6 && dice1 == 6))
 userMoney = userMoney + ( bet); 
 else
 userMoney = userMoney - ( bet);
 }
 return userMoney;
 }
 public static void main(String[] args)
 {
 // variables
 double userMoney;
 int option;
 double bet;
 //codes
 Scanner scan = new Scanner (System.in);
 System.out.println("enter your money: ");
 userMoney = scan.nextInt();
 System.out.println("enter your option 1 for odd 2 for even 3 for extreme: ");
 option = scan.nextInt();
 System.out.println("enter your bet: ");
 bet = scan.nextInt(); 
 System.out.println(money(userMoney, option, bet));
 userMoney = money(userMoney, option, bet); 
 }
}

• Andreas: Instead of using Math.random(), use a Random object.

Answer 1

(int) Math.random() * 6 + 1

means the same as

((int) Math.random()) * 6 + 1. 

You're first rounding down, then multiplying and adding.
As Math.random() returns as number 0 <= x < 1, it is always casted to 0. Notice that (int) always rounds down, so (int) 3.999 would become 3 for example, as well as (int)-3.9 would become -4.

Add braces like this:

 (int) (Math.random() * 6 + 1)

You can also wrap it into a function like this:

static int throwDice() {
 return (int) (Math.random() * 6 + 1);
}

Operators in Java have a specific precedence to them, like multiplication comes before addition in mathematics, unless you use braces. You can look it up here. When in doubt (or to clarify), use braces.

• Moritz Groß: No problem. Please accept my answer then by clicking the grey arrow left to it, so others can find it aswell.
• omer faruk coşar: of course it has time limit. after 2 min. ıll do it

Answer 2

The problem is at the time of initializing dice 1, dice 2. You must remember that you can't pass a primitive type by reference to a method. So you must wrap the COMPLETE DATA, which in this case is Math.random()*6+1 and parse the integer type. So, the code would be

dice1 = (int)(Math.random()*6+1); dice2 = (int)(Math.random()*6+1);