Open multiple tabs in selenium using python

Question

I have generated a list of links using selenium,i need to open each link in a separate tab.I have tried body.send_keys(Keys.CONTROL +"t") and body.send_keys(Keys.COMMAND+"t") but both didn't work(no errors but nothing happens), after searching for answers i found this link Opening new tabs selenium,however they mostly used java script(which works it opens a new tab) to run it which i can not seem to manipulate such as driver.execute_script('''window.open("http://bings.com","_blank");''') however i can not use this in a for loop as follows:

for link in links:
 #driver.execute_script("window.open('https://www.yahoo.com')")
 driver.execute_script("window.open('%s')")%link

Edit 1: To possible duplicate,the answers given that work are java script codes which works,however i can't use directly in a for loop.

Do i have to open a new random site (using the java script above) then driver.get(link) to get to my original link

If it matters i use python 2.7 on Linux.

• ivan_pozdeev: Possible duplicate of Selenium multiple tabs at once
• KunduK: Possible duplicate of stackoverflow.com/questions/54330431/…
• Amjasd Masdhash: @ivan_pozdeev please check question again,i clearly state that i know its asked before however the answers don't complete the answer i asked,the answers on that "Possible duplicate" simply forces me to open a tab(to a random site) then go to the original link . my question was to open new tab with original link.(Please check that link and my exact question before flagging)

Answer 1

You can create a control_string that you pass as your script:

links = ['https://www.yahoo.com', 'http://bings.com']
for link in links:
 control_string = "window.open('{0}')".format(link)
 driver.execute_script(control_string)