2

I want to convert this C++ code to Python v2:

static unsigned char asConvCode[3] = {0xFC, 0xCF, 0xAB};
void asConv(char* str, int size)
{
 int i = 0;
 for (i = 0; n< size; n++)
 {
 str[i] ^= asConvCode[n % 3];
 }
}

tried to make like that:

def asConv(self, data):
 asConvCode= [0xFC, 0xCF, 0xAB]
 for i in range(len(data)):
 data[i] ^= asConvCode[i % 3] # Error: Unsupported operand type(s) for ^=: ...
 return data

I will be happy for any hint

asked Mar 11, 2011 at 22:47
8
  • So what's wrong with the Python code you posted? Commented Mar 11, 2011 at 22:49
  • 1
    BTW, your return data is on the wrong indentation level. Commented Mar 11, 2011 at 22:50
  • @David: The OP already posted the error message, as a comment in the code. Commented Mar 11, 2011 at 22:50
  • 1
    But the important detail (which types are unsupported) is missing... Commented Mar 11, 2011 at 22:52
  • @delnan: It's actually pretty obvious if you notice that data is a string (as that's the intent of the C code). Commented Mar 11, 2011 at 22:54

1 Answer 1

2

In Python, characters in strings are simply strings of length 1, not integers. So you must use this:

data[i] = chr(ord(data[i]) ^ asConvCode[i % 3])

Also, as I wrote in a comment, your return data is at the wrong indentation level, and will cause your function to return after processing the first character.

answered Mar 11, 2011 at 22:52
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