Generate possible values for dice rolls

Question

I need a program in java that is capable to generate all possible combination of a dice roll. The number of dice as well as faces in dice may vary. for example. A combination of 3 six faced dice may be as follows. 111 112 113 114 115 116 121 122 123 124 125 126... and so on.... until 666. any help??? some kind of

public Map generatePossibleNumbers(int face, int numberOfDice){
 // generate numbers and return map
 Map generatedMap=new HashMap();
 return generatedMap;
}

Thanks in advance

• zero298: Stack Overflow is not a code writing service.
• Hari Babu: Sorry bro i was asking advice.. mr zero... you may not answer if you dont wish...
• Code-Apprentice: I suggest you try to generate more of the sequence by hand. Start to look for patterns. Then describe in words the steps you need to take to solve the problem.

Answer 1

I would recommend using a Collection instead of a Map since you are not going to need to store Key-Value pairs.

This is what I came up with:

public static void diceRoll(int dice, int numberOfDice) {
 Deque<Integer> list = new ArrayDeque<>(dice);
 diceRoll(dice, numberOfDice, list); // initially we have chosen nothing
}
// Private recursive helper method to implement diceRoll method.
// Adds a 'list' parameter of a list representing
private static void diceRoll(int dice, int numberOfDice, Deque<Integer> list) {
 if (dice == 0) {
 // Base Case: nothing left to roll. Print all of the outcomes.
 System.out.println(list);
 } else {
 // Recursive case: dice >= 1.
 for (int i = 1; i <= numberOfDice; i++) {
 list.addLast(i); // choose
 diceRoll(dice - 1, numberOfDice, list); // explore
 list.removeLast(); // un-choose
 }
 }
}

• codemirel: No problem. But please try to understand the code, not just copy it. ;)
• Hari Babu: Yes i fugured, you recursively called the method... that was real helpful :)