SQL Formatter for Scala.
This is a bridge to these libraries.
- Running on jvm, calls https://github.com/vertical-blank/sql-formatter
- Running on js, calls https://github.com/zeroturnaround/sql-formatter
libraryDependencies += "com.github.vertical-blank" %% "scala-sql-formatter" % "1.0.1"
libraryDependencies += "com.github.vertical-blank" %%% "scala-sql-formatter" % "1.0.1" scalaJSLinkerConfig ~= { _.withModuleKind(ModuleKind.CommonJSModule) }
You can easily use com.github.vertical_blank.sqlformatter.scala.SqlFormatter :
SqlFormatter.format("SELECT * FROM table1")
This will output:
SELECT * FROM table1
You can pass dialect with FormatConfig :
SqlFormatter.format( "SELECT *", FormatConfig(dialect = SqlDialect.CouchbaseN1QL))
Currently just four SQL dialects are supported:
- StandardSQL - Standard SQL
- CouchbaseN1QL - Couchbase N1QL
- DB2 - IBM DB2
- PLSQL - Oracle PL/SQL
Defaults to two spaces.
You can pass indent string with FormatConfig to format :
SqlFormatter.format( "SELECT * FROM table1", FormatConfig(indent = " "))
This will output:
SELECT * FROM table1
You can pass Seq to formatWithIndexedParams, or Map to formatWithNamedParams :
// Named placeholders SqlFormatter.formatWithNamedParams("SELECT * FROM tbl WHERE foo = @foo", params = Map("foo" -> "'bar'")) // Indexed placeholders SqlFormatter.formatWithIndexedParams("SELECT * FROM tbl WHERE foo = ?", params = Seq("'bar'"))
Both result in:
SELECT * FROM tbl WHERE foo = 'bar'
Same as the format method, both formatWithNamedParams and formatWithIndexedParams accept FormatConfig.