Uniformization (set theory)
In set theory, a branch of mathematics, the axiom of uniformization is a weak form of the axiom of choice. It states that if {\displaystyle R} is a subset of {\displaystyle X\times Y}, where {\displaystyle X} and {\displaystyle Y} are Polish spaces, then there is a subset {\displaystyle f} of {\displaystyle R} that is a partial function from {\displaystyle X} to {\displaystyle Y}, and whose domain (the set of all {\displaystyle x} such that {\displaystyle f(x)} exists) equals
- {\displaystyle \{x\in X\mid \exists y\in Y:(x,y)\in R\},円}
Such a function is called a uniformizing function for {\displaystyle R}, or a uniformization of {\displaystyle R}.
To see the relationship with the axiom of choice, observe that {\displaystyle R} can be thought of as associating, to each element of {\displaystyle X}, a subset of {\displaystyle Y}. A uniformization of {\displaystyle R} then picks exactly one element from each such subset, whenever the subset is non-empty. Thus, allowing arbitrary sets X and Y (rather than just Polish spaces) would make the axiom of uniformization equivalent to the axiom of choice.
A pointclass {\displaystyle {\boldsymbol {\Gamma }}} is said to have the uniformization property if every relation {\displaystyle R} in {\displaystyle {\boldsymbol {\Gamma }}} can be uniformized by a partial function in {\displaystyle {\boldsymbol {\Gamma }}}. The uniformization property is implied by the scale property, at least for adequate pointclasses of a certain form.
It follows from ZFC alone that {\displaystyle {\boldsymbol {\Pi }}_{1}^{1}} and {\displaystyle {\boldsymbol {\Sigma }}_{2}^{1}} have the uniformization property. It follows from the existence of sufficient large cardinals that
- {\displaystyle {\boldsymbol {\Pi }}_{2n+1}^{1}} and {\displaystyle {\boldsymbol {\Sigma }}_{2n+2}^{1}} have the uniformization property for every natural number {\displaystyle n}.
- Therefore, the collection of projective sets has the uniformization property.
- Every relation in L(R) can be uniformized, but not necessarily by a function in L(R). In fact, L(R) does not have the uniformization property (equivalently, L(R) does not satisfy the axiom of uniformization).
- (Note: it's trivial that every relation in L(R) can be uniformized in V, assuming V satisfies the axiom of choice. The point is that every such relation can be uniformized in some transitive inner model of V in which the axiom of determinacy holds.)
References
[edit ]- Moschovakis, Yiannis N. (1980). Descriptive Set Theory . North Holland. ISBN 0-444-70199-0.