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Talk:Struve function

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Error in hypergeometric definition

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I believe there is an error in the definition of H_v(z) using the 1F2 hypergeometric function (the last formula on the page). In the first factor, the term (z/2)^(alpha + 1/2) should simply be (z/2)^alpha. See Abramowitz and Stegun 12.1.21 (1964).

Maybe someone who knows how to edit wiki pages can fix this?

--Ryan — Preceding unsigned comment added by 65.128.10.151 (talk) 00:32, 20 April 2012 (UTC) [reply ]

Error in section "Relation to other functions"?"

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According to

the upper bound in the sum of the second formula should be

n 3 2 {\displaystyle {\begin{aligned}\left\lceil {\frac {n-3}{2}}\right\rceil \end{aligned}}} {\displaystyle {\begin{aligned}\left\lceil {\frac {n-3}{2}}\right\rceil \end{aligned}}}

instead of

n 1 2 {\displaystyle {\begin{aligned}\left\lfloor {\frac {n-1}{2}}\right\rfloor \end{aligned}}} {\displaystyle {\begin{aligned}\left\lfloor {\frac {n-1}{2}}\right\rfloor \end{aligned}}} — Preceding unsigned comment added by 2A0F:FF00:256:4300:A04F:EC4C:2D4A:1829 (talk) 01:00, 16 April 2024 (UTC) [reply ]

Addition to "Relation to other functions"

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I stumbled onto this relationship with the iterated sine integral using WolframAlpha, I hope someone with more math knowledge than me can expand on or explain this:

1 π 0 π sin ( sin ( x ) ) d x = H 0 ( 1 ) {\displaystyle {\frac {1}{\pi }}\int _{0}^{\pi }\sin(\sin(x))dx=\mathbf {H} _{0}(1)} {\displaystyle {\frac {1}{\pi }}\int _{0}^{\pi }\sin(\sin(x))dx=\mathbf {H} _{0}(1)}

AltStyle によって変換されたページ (->オリジナル) /