Haskell/Solutions/Variables and functions
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quadruplex=double(doublex) quadruple5=double(double5) quadruple5=double10 quadruple5=20
subtractHalfx=x/2-12
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volumeBoxwhd=w*h*d
One approach for the Giza problem is starting from the pyramid volume and the estimated stone volume. Using general functions for the task, that might look like this in GHCi:
Prelude> let volumeBox w h d = w * h * d -- Just as above. Prelude> let volumeSquarePyramid b h = b * b * h / 3 Prelude> volumeSquarePyramid 230.4 146.5 / volumeBox 1 1 1 2592276.48
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volumeCylinderrh=h*arear