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This question was originally posted on mathoverflow. Having obtained no answers after one month, I've decided to cross-post it here.


Let $H = ( V, E )$ be a $k$-uniform connected hypergraph, with $n = |V|$ vertices and $m = |E|$ hyperedges. Let $O_w$ be the number of distinct edge induced subgraphs of $H$ having $w$ vertices and an odd number of hyperedges. Let $E_w$ be the number of distinct edge induced subgraphs of $H$ having $w$ vertices and an even number of hyperedges. Let $\Delta_w = O_w - E_w$.

Let $b_w$ be the number of bits required to encode $\Delta_w,ドル i.e. $b_w = log_2 \ \Delta_w$.

Let $b = \displaystyle\max_{\substack{w}} b_w$.

I'm interested in how $b$ grows. I would like to determine the best possible upper bound for $b$ which is expressible as a function of only $n,ドル $m$ and $k$. More precisely, I would like to determine a function $f(n,m,k)$ having both the following properties:

  1. $b \leq f( n, m, k )$ for any $k$-uniform hypergraph $H$ having $n$ vertices and $m$ hyperedges.
  2. $f(n,m,k)$ grows slower than any other function which satisfies the 1st property.

In general both $O_w$ and $E_w$ are exponential in $m,ドル therefore I expect that their difference $\Delta_w$ is not exponential in $m$ and thus that $b \in o( m )$.

However for the moment I've no clue on how to try to prove this.

Questions

  • How does $b$ grow with respect to $n,ドル $m$ and $k$?
  • Are there any relevant results in the literature?
  • Any hint on how to try to prove $b \in o(m)$?
asked Oct 9, 2013 at 18:49
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1 Answer 1

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It is the case that $b \notin o( m )$.

Let $G = ( V_G, E_G )$ be a 3ドル$-regular connected graph. Without loss of generality, let us fix $w = |V_G|$ and focus on $\Delta_{|V_G|} = O_{|V_G|} - E_{|V_G|}$.

Pick an arbitrary edge $e = \{u, v\} \in E_G$. Remove $e$ and replace it with the following gadget:

Gadget

This has the effect of multiplying $\Delta_{|V_G|}$ by 8ドル$. The resulting graph $H = (V_H, E_H)$ is still 3ドル$-regular connected, and has 60ドル$ vertices more than $G$.

By repeating this process $i$ times, we obtain a 3ドル$-regular connected graph having $|V_H| = |V_G| + 60i$ vertices, and whose $\Delta_{|V_H|}$ is 8ドル^i$ times bigger than $\Delta_{|V_G|}$.

After $i = \frac{|V_G|}{3}$ iterations, our final graph will have $|V_H| = 21|V_G|$ vertices and a $\Delta_{|V_H|}$ which is 2ドル^{|V_G|}$ times bigger than the $\Delta_{|V_G|}$ we started with. Let $n = |V_H|,ドル recall how $m = 1.5n$ for 3ドル$-regular graphs, and we get a $\Delta_{|V_H|}$ whose absolute value is lower-bounded by 2ドル^{\frac{m}{31.5}}$. Henceforth $b$ is linear in $m$ in the worst case, and thus it cannot belong to $o( m )$.

Contrarily to intuition (at least mine), the number of edge covers of odd cardinality and the number of edge covers of even cardinality may diverge by an exponential amount.

answered Jan 20, 2016 at 7:42
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