This question is about an answer in question
Bjørn Kjos-Hanssen answer states that:
You can first show that the halting problem (the set 0ドル'$) can be used to compute a set $G\subseteq\mathbb N$ that is 1-generic meaning that in a sense each $\Sigma^0_1$ fact about $G$ is decided by a finite prefix of $G$. Then it is easy to prove that such a set $G$ cannot be computable (i.e., decidable).
I have trouble understanding this sentence as I am new to forcing. For example, what does "finite prefix" mean here? Can someone explain this sentence? (I know what $\Sigma^0_1$ means.)
Can someone explain the general idea behind forcing? I am also looking for easy to read introductions articles and books about forcing.
edit: So, how can we prove that each $\Sigma_1^0$ fact about $G$ being decided by a finite prefix leads to the fact that $G$ cannot be computable?
-
$\begingroup$ I edited the question to make it more interesting. I hope that I kept the original intention. Feel free to roll back or edit. $\endgroup$Kaveh– Kaveh2013年03月02日 08:02:13 +00:00Commented Mar 2, 2013 at 8:02
1 Answer 1
A finite prefix of $G$ is $G \cap \{0,1,\ldots n\}$ for some $n$. It is easier if you look at the characteristic function of $G$ which can we viewed as an infinite word in 2ドル^\omega$. Then a finite prefix is a finite initial part of $G$.
For forcing, there are many resources, depends on what you want to learn. A point to start is the Wikipedia pages and the references listed there: Forcing (set theory), Forcing (recursion theory). Timothy Chow's article A Beginner's Guide to Forcing is a good introduction.
-
$\begingroup$ While the links are relevant, they certainly do not give enough information to complete the proof outlined by Bjorn. In particular the page on Forcing and recursion theory is atrocious. $\endgroup$cody– cody2013年04月03日 14:13:06 +00:00Commented Apr 3, 2013 at 14:13
-
$\begingroup$ @cody, that question was added after my answer. I answered what was originally asked. And I am not sure it is a good idea to give an introduction to forcing here when Tim has already written a very good and readable introduction to it. As I see it the OP in place of reading the easy to read reference he asked for wants us to explain it even simpler. Feel free to do so, but I am not sure I will. $\endgroup$Kaveh– Kaveh2013年04月03日 14:45:33 +00:00Commented Apr 3, 2013 at 14:45
-
$\begingroup$ I really like Tim's introduction! However he makes no no mention of 1-genericity or give any mention to computability, which is what I meant by "not enough information to complete the proof outline". $\endgroup$cody– cody2013年04月03日 15:24:36 +00:00Commented Apr 3, 2013 at 15:24
-
$\begingroup$ @cody, OK, I will try to address that (I don't have much free time right now, and I am hoping that Tim himself or someone else (Josh, Andrej, Emil, ...) will answer it before I find time :). $\endgroup$Kaveh– Kaveh2013年04月03日 16:36:31 +00:00Commented Apr 3, 2013 at 16:36
-
$\begingroup$ Thanks! I'll admit that I am interested in the answer to this question as well. $\endgroup$cody– cody2013年04月03日 18:49:34 +00:00Commented Apr 3, 2013 at 18:49
Explore related questions
See similar questions with these tags.