Print 0 to 100 without 1-9 characters

Question

Print integers 0 to 100 (inclusive) without using characters 123456789 in your code.

Separator of numbers can be comma or white space (by default <blank>, <horizontal tabulator>, <newline>, <carriage return>, <form feed> or <vertical tabulator>).

Shortest code wins.

• Arnauld: Many tricks are made possible by allowing 0. Which is what makes this challenge interesting, IMO.
• Purple P: I thought "do X without Y" questions weren't allowed anymore.
• rydwolf: @PurpleP They're allowed, but discouraged. Interesting ones are fine.
• spuck: Is there a requirement to stop printing at 100?
• user100411: Can I use non-ASCII encoding?

Answer 1

R, 9 bytes

F:volcano

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The sequence operator : coerces its arguments to integers. F is the boolean FALSE, which gets coerced to 0. volcano is one of the many built-in datasets (it gives topographic information about Maunga Whau in New Zealand); since it is a matrix, : fetches the value at position [1, 1] which is luckily equal to 100. The code is therefore equivalent to 0:100.

This answer was inspired by a conversation with Giuseppe and Kirill L. in the comments under Giuseppe's R answer.

• caird coinheringaahing: I thought Mathematica had weird builtins. Why is volcano specifically about Maunga Whau in New Zealand?
• Robin Ryder: @cairdcoinheringaahing This dataset was digitized by Ross Ihaka, a New Zealand statistician and one of the creators of R, who then included it in R as a good example for a contour map. I don't know why he chose that volcano; maybe he lived nearby, or maybe that was just the first map he found!
• Robin Ryder: @Giuseppe I tried that, but volcano is the only dataset whose first entry is in \$[100, 101)\$. Using anything else than the first entry leads to at least 9 bytes, even for a dataset with a 3-character name (e.g. sum(BOD) or npk[pi], which don't give 100 anyway). I don't think it can get shorter using this approach.
• Darrel Hoffman: Not that it'd change your byte-count, but you could've just used 0 - the rules only say 1-9 are forbidden...
• avarice: Just impressed by the beauty of this answer!

Answer 2

Python 3: (削除) 27 (削除ここまで) (削除) 23 (削除ここまで) 20 Bytes

Thanks to caird coinheringaahing for -4 bytes, ovs for -3 bytes

print(*range(*b'e'))

I'm pretty poor at golfing, so there's probably a better way to do this.

TIO

• caird coinheringaahing: 23 bytes
• ovs: You can replace ord('e') with *b'e' for -3 bytes.
• ovs: Strings with a leading b are objects of type bytes, which behave like lists of integers in many ways. This is doing the same as range(*[101]).
• User 12692182: Byte strings have special iteration built-in to them. This code snippet should help clarify: for char in b'hello': print(char)
• Jonathan Allan: @aneroid - that would be a snippet rather than a function or program, so would need to be lambda:[*range(*b'e')] to comply with site defaults, making it longer than the full program print(*range(*b'e')).

Answer 3

JavaScript (V8), 28 bytes

We cannot write \100ドル\$ or \101ドル\$ in hexadecimal with 0's and letters only (0x64 and 0x65 respectively), but we can write \202ドル\$ (0xCA) and use \2ドルn<202\$ as the condition of the for loop.

for(n=0;n+n<0xCA;)print(n++)

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30 bytes

This version computes \10ドル^2\$ with the hexadecimal representation of \10ドル\$.

for(n=0;n<=0xA*0xA;)print(n++)

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31 bytes

This version builds the string "100".

for(n=0;n<=-~0+'00';)print(n++)

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• Robin Ryder: The last one could be 1 byte shorter asfor(n=0;n<=0xA+'0';)print(n++).

Answer 4

brainfuck, 138 bytes

>>++++++++++<<++++++[>>>++++++++<<<-]++++++[>>>>++++++++<<<<-]++++++++++>++++++++++<[>[>>.>.+<<.<-]++++++++++>>>----------<+<<<-]>>>>+.-..

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No numbers is pretty easy, but the golf size is not great... :)

I am sure it can be improved, I am really a beginner in using Brainfuck. I wanted to try it anyway.

How it works:

>>++++++++++<< LF Char (idx2)
++++++[>>>++++++++<<<-] Zero char tens (idx3)
++++++[>>>>++++++++<<<<-] Zero char unit (idx4)
+++++ +++++ 10 counter (tens)
>+++++ +++++< 10 counter (unit)
[> Move to the counter
 [>>. Print the tens
 >.+ Print the unit and increment
 <<. Print the LF
 <-] Loop 10 times
+++++ +++++ Restore the counter
>>>----- ----- Restore the digit
 <+ Increment the tens char
 <<<-] Loop everything 10 times
>>>>+.-.. Print 100 using a cell which is already at char 0

• caird coinheringaahing: Welcome to the site, and nice first answer!

Answer 5

SHENZHEN I/O, 61 bytes, 7,円 7 Lines

@not
@mov acc dat
@not
tgt acc dat
-mov acc p0
-add x0
slp x0

Outputs 0-100 as simple output, one per time unit. Makes use of the DX300 (XBus <-> Simple Input chip) and LC70G04 (NOT gate), which cost 1\ each but do not use any power or count as lines of code (the game's measure of code length). These are used to generate a value of 1, which it adds and outputs until it hits 100. The value for 100 is generated using the "not" command, which makes the accumulator 100 if it is value 0, otherwise it sets the acc to 0.

(Not pictured: conversion from simple output to the screen's XBus input, for the visualization.)

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SHENZHEN I/O (MCxxxx ASM only), 129 bytes, 8,円 16 Lines

@not | not
@mov acc p0 | mul acc
@mov acc dat | dgt 0
@not | sub p0
add p0 | dgt 0
tgt acc dat | mul acc
-mov acc x0 | mov acc p0
slp p0 | slx x0

Outputs 0-100 as one XBus output each. Uses only programmable MCxxxx chips, no logic gates or other components. Generates value 1 in a pretty interesting way:

not # acc = 100
mul acc # 100 * 100 = 999 (max value)
dgt 0 # digit 0 of 999 = 9
sub p0 # 9 - 100 = -91
dgt 0 # digit 0 of -91 = -1
mul acc # -1 * -1 = 1

enter image description here

• Natelolzzz: Nice to see a little more Shenzen I/O rep around here!

Answer 6

Vyxal jHRM, 0 bytes

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Kinda cheating, but whatever.

How?

 # full program
 # H flag presets the stack to 100
 # R flag does range when number is treated as iterable
 # M flag makes range start at 0
 # j flag joins the top of the stack by newlines

Answer 7

Jelly, 2 bytes

3Ż

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Outputs a list. If the separator must be a single character, 3 bytes

How it works

3ŻK - Main link. Takes no arguments
3 - Yield 100
 Ż - Range from 0 to 100
 K - Join by spaces (optional)

• azro: wtf happens here xD
• Martin Braun: Languages designed to be used in code golf kinda ruin the aesthetics of code golf. I prefer to see mad-squeezing of daily used languages that are legitimately used in real production environments, instead.
• caird coinheringaahing: @MartinBraun In most challenges (I.e. those more complex than this), creating a competitive answer in a golfing language is just as difficult as doing so in a "real" language. You’ll see that I helped golf the Python answer just above (sorting by votes), and I can tell you that was just as simple as writing this answer
• Rushabh Mehta: @MartinBraun This opinion has been shared a gazillion times on meta. The consensus is, just look at other answers. The R answer in particular is quite beautiful.
• caird coinheringaahing: @Sanctus It is 2 bytes. More specifically, it is the hex bytes 83 D2 (and 4B for the 3 byte version). Jelly uses a custom code page to encode its programs in order to make them more "readable", but if you fed a raw byte stream of those two bytes into the Jelly interpreter, it would produce the same output

Answer 8

Raku, 10 bytes

put 0..C

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C here is the Unicode character ROMAN NUMERAL ONE HUNDRED.

Any other Unicode character with a defined value of 100 could be used:

௱: TAMIL NUMBER ONE HUNDRED
൱: MALAYALAM NUMBER ONE HUNDRED
፻: ETHIOPIC NUMBER HUNDRED
c: SMALL ROMAN NUMERAL ONE HUNDRED
佰: CJK UNIFIED IDEOGRAPH-4F70
百: CJK UNIFIED IDEOGRAPH-767E
陌: CJK UNIFIED IDEOGRAPH-964C

All are three UTF-8 bytes long, like C.

• user0721090601: Anytime you have 0..foo, you can use ^foo. So you can get 8 bytes with put ^C
• Sean: @user0721090601 Incorrect. ^foo is the same as 0..(foo-1), not 0..foo.
• user0721090601: Ack, duh. Ignore me
• caird coinheringaahing: Are there any Unicode characters with a defined value of 101? If so, puts ^ then the character would save bytes
• Sean: @cairdcoinheringaahing I checked that before posting my answer, but there aren't any. Not too surprising, really.

Answer 9

R, 11 bytes

F:(0xA*0xA)
F:0xA^(T+T)

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Uses this tip.

Still being beaten by some volcano in New Zealand, though...

Old answer:

R, 16 bytes

F:paste0(+T,0,0)

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Thanks to Kirill L. for correcting an error.

R's ASCII=>byte function is utf8ToInt, which unfortunately has an 8 in it. Luckily, : will attempt to coerce its arguments to numeric types, so we construct 100 by pasting together +F (which coerces its value to 0) and two 0s. This would also work, though longer, without a 0 as F:paste(+T,+F,+F,sep="").

Possibly there's a very short builtin dataset with a sum that's close to 100, though I haven't been able to find one.

• Kirill L.: I believe according to the task, you should start with F rather than T.
• Robin Ryder: 9 bytes (but yours is much more elegant!)
• Giuseppe: @KirillL. oh yes, my mistake. Thanks.
• Kirill L.: @Giuseppe, yeah, but F:sum(T|Nile) is still only 13 bytes.
• Robin Ryder: I found out that the volcano dataset leads to a 9 byte answer, which I posted instead.

Answer 10

Retina 0.8.2, (削除) 33 (削除ここまで) (削除) 26 (削除ここまで) 24 bytes

,,
,,,,,,
,
,,,,,
$.`

Try it online! Explanation: The first stage inserts two commas, which the second stage increases to 20 (it's complicated). The third stage multiplies by 5 to give 100. The last stage then inserts the number of commas so far at each position.

• Leo: Nice! You can golf it a bit by computing 100 as 4*5*5 tio.run/##K0otycxL/P@fSwcIuHTAFILmUtFL@P8fAA
• Neil: @Leo You should have used 0514150 commas for a nice symmetry!
• Neil: @Leo (Although as it happens I found a shorter solution, which I then verified using a Python script. The only other solution with the same length simply has the first two stages swapped.)
• Kai Burghardt: As per specification you may not use commas (,).
• Neil: @KaiBurghardt I think that's just the way the list of excluded digits is formatted. But you can replace the commas with spaces or ¶s to get an alternative program if you so wish.

Answer 11

C (gcc), 38 bytes

f(i){for(i=0;printf("%d ",i++)&'#';);}

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Without using digit 0, it would be 39 bytes: i;main(){for(;printf("%d ",i++)&'#';);}

• Michael Dorgan: i as a global defaults to 0 saving a couple characters. Just change your main call to f in your example/
• Michael Dorgan: Actually took I it further and made it recursive for a 2 more characters saved:
• vijay kumar: where did you learn this level of programming i don't even understand it
• tsh: @vijaykumar printf returns how many bytes are printed. '#' is as same as number 35 (ASCII 35 for "#"). That's all you need to know to make it work.
• Michael Dorgan: Capital C would also work - 64+3 = 'C' :)

Answer 12

Zsh, 12 bytes

seq 0 $[##d]

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• seq: count
  • from 0
  • $[##d]: to the character value of d

Alternative:

Zsh, 12 bytes

!
seq 0 $?00

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! does nothing, but fails with exit code 1; $? then retrieves the exit code.

• roblogic: Also, jot $[##d]

Answer 13

Bash, (削除) 25 (削除ここまで) 23 bytes

seq 0 $(printf %d "'d")

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-2 thanks to @manatwork

• manatwork: Using $(..) is good coding habit, but is longer than `..`. And no need to quote "%d" as contains nothing special. In change the "'d" contains character with special meaning, but only one, so escaping it with \ is shorter. Try it online!
• Jonah: What is happening with the 'd? I assume printf is interpreting it as its ascii numeric value but I don't see it mentioned in the docs.
• avarice: @manatwork thanks!
• manatwork: How weird, @Jonah. I can't find where I learned about that feature. Only found in the printf specification's Examples section. Maybe Wasif knows a better documentation.
• avarice: @Jonah found it few days ago here, Actually I don't know a lot of documentation on bash

Answer 14

PowerShell, (削除) 16 (削除ここまで) 12 bytes

-4 bytes thanks to @mazzy!

0..(0xa*0xa)

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• mazzy: Try it online!
• Zaelin Goodman: @mazzy thanks! I feel silly for having missed that, lol
• Walter Mitty: You beat me to it!
• Can.U: Why not just enter 0..100

Answer 15

PHP, 30 bytes

First time golfing, I hope I posted this right!

while($q<ord(e))echo+$q++,' ';

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---

Thanks to manatwork and Dewi Morgan's suggestions to improving the code! From 34 to 30 bytes!

_{The code revisions are in the edit history, removed here so it looks cleaner!}

• rydwolf: Welcome to Code Golf! Nice first answer. (Don't worry, you posted it correctly :p)
• manatwork: Unfortunately your solution doesn't output 0. While fixing it, you could reduce its size by removing the single quotes, the braces and the parenthesis around echo's argument. I would suggest this: Try it online!
• Dewi Morgan: Nice! The space before quotes can go, too :)
• Dewi Morgan: Thinking about it, you can also get rid of the third clause if you postincrement and concatenate the variable to the space : `for($q=0;$q<ord(e);)echo$q++." "; Shame none of the permitted separators are characters so they could be unquoted.
• Dewi Morgan: And we only need the 4 chars $q=0 because null isn't being cast to an int. We can cast to an int to avoid it, but (int) takes 5 bytes. But adding 0 casts to 0, and we can only do that in 2 bytes, though we need to re-add the space after the echo, so it's effectively 3. Still saves us a byte, though! while($q<ord(e))echo 0+$q++." "; (while has the same bytecount as for with just the middle clause used).

Answer 16

Factor, (削除) 46 (削除ここまで) 23 bytes

^{-23 bytes thanks to Bubbler}

0xa sq [0,b] [ . ] each

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I've never written anything in Factor before, but it's a surprisingly fun language.

• Bubbler: Thanks for picking up Factor! Lots of golfs are possible on this code. 1) You don't need to dup the 100 in the first place, and then you won't have anything to drop at the end. 2) A range is a sequence, so you can run each on it without >array. 3) There are multiple ways to get the constant 100, such as CHAR: d or 0xa sq. If you want, drop by the Factor chatroom, and I'll explain things further :)

Answer 17

dc, 13 characters

Thanks to

• Daemon for reusing stack depth instead of getting it again, to use shorter operator (-1 character)

[zpdA0>x]dsxx

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dc, 14 characters

Thanks to

• Digital Trauma for the twist in using the stack depth efficiently (-2 characters)

[zpzA0!<m]dsmx

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dc, 16 characters

0[pz+dA0>i]dsixp

Sample run:

bash-5.0$ dc -e '0[pz+dA0>i]dsixp' | head
0
1
2
3
4
5
6
7
8
9

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• Digital Trauma: Similar idea, same score
• manatwork: Thanks @DigitalTrauma. I tried that too earlier, but only now, seeing your suggestion I found the more efficient way.

Answer 18

Ruby (削除) 22 bytes (削除ここまで) 12 bytes - thanks to @manatwork

p *0..?d.ord

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• manatwork: A splat * operator will do it instead of .to_a: p *0..?d.ord
• pxeger: You can switch to Ruby 1.8 and remove the .ord

Answer 19

Vyxal, jH, 1 byte

ʀ

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Flags for the win. The H flag presets the stack to 100, generate range 0 to 100 and then j flag joins on newlines. The flag was around before this challenge too.

• user7467: This seems to give the wrong output
• lyxal: @Anush its fixed
• avarice: +1, first reaction someone seeing this will be "OMGWTFBBQ wat happens here" XD

Answer 20

Perl, (削除) 20 (削除ここまで), (削除) 13 (削除ここまで), (削除) 12 (削除ここまで), 16 bytes

say for 0..ord d 

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• Sake: You can get rid of ,ドル=",";, but you need ord('d') for it to work.
• Thor: @PaulPicard: unquoted dee works here (perl v5.32.0), e.g. perl -E 'say 0..ord(d)'
• manatwork: You can remove the parenthesis.
• Xcali: Without the comma, this doesn't meet the challenge specification to have a separator between numbers. say for 0..ord d would meet the rules.
• Thor: @Xcali: indeed, thanks

Answer 21

Zsh, 16 bytes

echo {0..$[##d]}

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Only builtins, so no seq

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For fun, here's a 17 byte answer without 0:

echo {$?..$[##d]}

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Also $! or $# will work as 0 replacements.

• roblogic: Coreutils solution for 14B: jot - 0 $[##d]

Answer 22

Bash, (削除) 18 (削除ここまで) (削除) 16 (削除ここまで) 14 bytes

seq 0 $[++x]00

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Thanks @manatwork for -2, @Jonah for -2

• manatwork: You don't need the braces.
• rydwolf: Welcome to Code Golf! Nice first answer.
• Jonah: seq 0 $[++x]00 for 14.

Answer 23

Perl 5 (ppencode-compatible), 64 bytes

You didn't clarify that I must separate each with exactly one character, so here it is mine.

print length uc xor s qq q xor print while length ne ord qw q eq

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Explained

 # print(length) did not work for zero as $_ is not defined at then
 print length uc xor
 s qq q xor
 # delimiter
 print
while
 # equals to: length ne 101
 length ne ord qw q eq

Answer 24

Bash, 15

seq `dc<<<A0Kf`

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• 1 byte saved, thanks to @manatwork.

---

Previous answer:

Pure Bash (no external utilities), 23

• 9 bytes saved thanks to @ArcticKona.

eval echo {0..$[++x]00}

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• manatwork: Your newest solution skips "0" because you missed a space between seq's parameters. Sorry, that looks like +1 character. ☹
• Digital Trauma: @manatwork oops - yes, thanks - fixed.
• manatwork: As apology, here is a 15 character one, still based on your idea: seq `dc<<<A0Kf`.
• Digital Trauma: @manatwork - thanks!
• Arctic Kona: for pure bash try eval echo {0..$[++x]00}

Answer 25

PICO-8, (削除) 50 (削除ここまで) 45 bytes

i=0-#"0"repeat i+=#"0"?i
until#tostr(i)>#"00"

-5 bytes by replacing print with its shorthand, ?.

Demo (50 byte version; 45 byte version has same output):

i=0-#"0"repeat i+=#"0"print(i)until#tostr(i)>#"00"

• SjoerdPennings: Glad to see some PICO-8 on CGCC! It's such a fun little engine to tinker around with.

Answer 26

Javascript, 48 bytes

for(a of Array("e".charCodeAt()).keys())alert(a)

Can be shorter, if you allow in reverse (36 chars)

for(i="e".charCodeAt();--i;)alert(i)

• manatwork: Your 50 bytes solution doesn't output 0. To fix it just remove that unnecessary pre-incrementation and change the "d" to "e".
• user100752: @manatwork i thought we didnt have to print 0, at the time i wrote the solution. I'll fix it :) thanks
• l4m2: 40 forward

Answer 27

Python, (削除) 25 (削除ここまで) 23 bytes

print(*range(ord('e')))

-2 by Steffan, remove first parameter (0) from call to range

• naffetS: The 0, is not needed
• Eric Xue: Thanks a lot! I'll use it.
• vengy: 21 bytes Try it online!

Answer 28

GNU Octave, (削除) 14 (削除ここまで), 5 bytes

0:'d'

TIO by Giuseppe

• Giuseppe: I think just 0:'d' should work.
• Thor: @Giuseppe: nice one
• Giuseppe: Also, Octave is on TIO if you want to add a link :-)

Answer 29

05AB1E, 2 bytes

тÝ

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Outputs a list. If the separator must be a single character, 3 bytes

How it works

тÝ» - Full program
т - Push 100
 Ý - Range from 0 to 100
 » - Join with newlines (optional)

Answer 30

Deadfish~, 2071 / 8 / 7 bytes

2071 bytes

o{i}c{d}io{i}dc{d}iio{i}ddc{d}iiio{i}dddcddddddoiiiiiicdddddoiiiiicddddoiiiicdddoiiicddoiicdoicociodciioddciiiodddciiiioddddciiiiiodddddciiiiiioddddddc{i}dddo{d}iiic{i}ddo{d}iic{i}do{d}ic{i}o{d}c{i}io{d}dc{i}iio{d}ddc{i}iiio{d}dddc{i}iiiio{d}ddddc{i}iiiiio{d}dddddc{i}iiiiiio{d}ddddddc{i}{i}dddo{d}{d}iiic{i}{i}ddo{d}{d}iic{i}{i}do{d}{d}ic{i}{i}o{d}{d}c{i}{i}io{d}{d}dc{i}{i}iio{d}{d}ddc{i}{i}iiio{d}{d}dddc{i}{i}iiiio{d}{d}ddddc{i}{i}iiiiio{d}{d}dddddc{i}{i}iiiiiio{d}{d}ddddddc{i}{i}{i}dddo{d}{d}{d}iiic{i}{i}{i}ddo{d}{d}{d}iic{i}{i}{i}do{d}{d}{d}ic{i}{i}{i}o{d}{d}{d}c{i}{i}{i}io{d}{d}{d}dc{i}{i}{i}iio{d}{d}{d}ddc{i}{i}{i}iiio{d}{d}{d}dddc{i}{i}{i}iiiio{d}{d}{d}ddddc{i}{i}{i}iiiiio{d}{d}{d}dddddc{i}{i}{i}iiiiiio{d}{d}{d}ddddddc{{i}dddddd}dddo{{d}iiiiii}iiic{{i}dddddd}ddo{{d}iiiiii}iic{{i}dddddd}do{{d}iiiiii}ic{{i}dddddd}o{{d}iiiiii}c{{i}dddddd}io{{d}iiiiii}dc{{i}dddddd}iio{{d}iiiiii}ddc{{i}dddddd}iiio{{d}iiiiii}dddc{{i}dddddd}iiiio{{d}iiiiii}ddddc{{i}dddddd}iiiiio{{d}iiiiii}dddddc{{i}dddddd}iiiiiio{{d}iiiiii}ddddddc{{i}ddddd}dddo{{d}iiiii}iiic{{i}ddddd}ddo{{d}iiiii}iic{{i}ddddd}do{{d}iiiii}ic{{i}ddddd}o{{d}iiiii}c{{i}ddddd}io{{d}iiiii}dc{{i}ddddd}iio{{d}iiiii}ddc{{i}ddddd}iiio{{d}iiiii}dddc{{i}ddddd}iiiio{{d}iiiii}ddddc{{i}ddddd}iiiiio{{d}iiiii}dddddc{{i}ddddd}iiiiiio{{d}iiiii}ddddddc{{i}dddd}dddo{{d}iiii}iiic{{i}dddd}ddo{{d}iiii}iic{{i}dddd}do{{d}iiii}ic{{i}dddd}o{{d}iiii}c{{i}dddd}io{{d}iiii}dc{{i}dddd}iio{{d}iiii}ddc{{i}dddd}iiio{{d}iiii}dddc{{i}dddd}iiiio{{d}iiii}ddddc{{i}dddd}iiiiio{{d}iiii}dddddc{{i}dddd}iiiiiio{{d}iiii}ddddddc{{i}ddd}dddo{{d}iii}iiic{{i}ddd}ddo{{d}iii}iic{{i}ddd}do{{d}iii}ic{{i}ddd}o{{d}iii}c{{i}ddd}io{{d}iii}dc{{i}ddd}iio{{d}iii}ddc{{i}ddd}iiio{{d}iii}dddc{{i}ddd}iiiio{{d}iii}ddddc{{i}ddd}iiiiio{{d}iii}dddddc{{i}ddd}iiiiiio{{d}iii}ddddddc{{i}dd}dddo{{d}ii}iiic{{i}dd}ddo{{d}ii}iic{{i}dd}do{{d}ii}ic{{i}dd}o{{d}ii}c{{i}dd}io{{d}ii}dc{{i}dd}iio{{d}ii}ddc{{i}dd}iiio{{d}ii}dddc{{i}dd}iiiio{{d}ii}ddddc{{i}dd}iiiiio{{d}ii}dddddc{{i}dd}iiiiiio{{d}ii}ddddddc{{i}d}dddo{{d}i}iiic{{i}d}ddo{{d}i}iic{{i}d}do{{d}i}ic{{i}d}o{{d}i}c

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8 bytes (if you consider Hello, world! a valid separator)

o{{iow}}

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7 bytes (If you don't care about seperators)

o{{io}}

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Never thought I'd see deadfish be shorter than, well, anything except Unary.

• emanresu A: Damn it. Rewriting.
• emanresu A: @Razetime Remebered w doesn't care about accumulator.
• The Fifth Marshal: "Hello, World!" is not a valid separator.
• Caleb Fuller: Haha reading up on Deadfish~ I realized that exact 7 byte program... but you beat me to it! I actually wrote a Deadfish interpreter for Code Golf that automatically had spaces between output, just because the BASIC interpreter put them there. 😄 Perfect for than program!