Jelly, (削除) 15 (削除ここまで) 13 bytes

Øqż"[;,"FUƝFy

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-1 byte directly from emanresu A, and minus a second byte from a golf of that suggestion.

How it works

This exploits the leading constant chain structure in Jelly, wherein if a chain begins with a constant (Øq in this case), and is followed exclusively by monads and dyad-nilad pairs, the chain simply operates on the leading constant, ignoring any provided arguments, until this pattern is broken, saving us from having to use any grouping quicks while we construct the translation mapping.

Øqż"[;,"FUƝFy - Main link. Takes the string S on the left
Øqż"[;,"FUƝF - Leading constant chain:
Øq - Constant: "qwertyuiop"asdfghjkl"zxcvbnm"
 ż"[;," - Dyad-nilad: Zip with "[;,"
 F - Monad: Flatten; "qwertyuiop[asdfghjkl;zxcvbnm,"
 UƝ - Monad:
 Ɲ - Over overlapping pairs:
 U - Reverse
 F - Monad: Flatten; "wqewretrytuyiuoipo[pa[sadsfdgfhgjhkjlk;lz;xzcxvcbvnbmn,m"
 y - With the transliteration string on the left and S on the right, transliterate S according to the string

The way Jelly's transliterate atom, y, works when provided a flat string on the left is to break it up into adjacent pairs of characters, then replace the first character with the second in the target string on the right. So "wqewretrytuyiuoipo[pa[sadsfdgfhgjhkjlk;lz;xzcxvcbvnbmn,m"y transliterates

w -> q
e -> w
r -> e
...
, -> m

• \$\begingroup\$ 14 bytes with a different use of y. There's probably a 13 or even 12 in there somewhere. \$\endgroup\$

  emanresu A

  – emanresu A

  2024年07月09日 08:04:47 +00:00

  Commented Jul 9, 2024 at 8:04
• \$\begingroup\$ @emanresuA Indeed, there is! \$\endgroup\$

  caird coinheringaahing

  – caird coinheringaahing ♦

  2024年07月09日 16:20:44 +00:00

  Commented Jul 9, 2024 at 16:20

C++ (Windows MSVC), 92 bytes

#include<Windows.h>
void f(PCH s){for(;*s;)*s++=MapVirtualKey(OemKeyScan(*s)-(*s>32),1)|32;}

Take input as a char* (PCH is typedef of char*), output by modify the string in-place.

Trying to make use of some built-ins. But seems not quite short. Maybe some one may take this idea and make a shorter one in other languages.

OemKeyScan convert key to its scancode, 'q' -> 16, 'w' -> 17, 'e' -> 18, ..., 'p' -> 25, 'a' -> 30, ..., 'l' -> 38, 'z' -> 44, ..., 'm' -> 50. MapVirtualKey convert scancode back to (uppercase) character.

Saved 1 byte by ErikF.

• \$\begingroup\$ 87 bytes by removing the void and moving the increment into the assignment operator (works in a .c file, don't actually try it online): link \$\endgroup\$

  ErikF

  – ErikF

  2021年07月03日 02:33:15 +00:00

  Commented Jul 3, 2021 at 2:33
• 1
  \$\begingroup\$ @ErikF remove void would work if I change the language to C but not C++. \$\endgroup\$

  tsh

  – tsh

  2021年07月03日 02:50:54 +00:00

  Commented Jul 3, 2021 at 2:50
• \$\begingroup\$ Is there an online environment where I can run this? \$\endgroup\$

  sergiol

  – sergiol

  2025年05月15日 22:49:54 +00:00

  Commented May 15 at 22:49

J, 43 bytes

'qwertyuiop[asdfghjkl;zxcvbnm, '(<:@i:{[)]

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• 'qwertyuiop[asdfghjkl;zxcvbnm, ' The full keyboard, including the shifted away left-most chars and the extra chars [;,, as well as two extra spaces at the end.
• <:@i: Find the index of the input within that, searching from the right, and substract one.
• {[ Pull those shifted indexes from the string in step 1.

Vyxal, (削除) 16 13 (削除ここまで) 12 bytes

k•`[;,`Y∑:ǔL·

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k• # Qwerty keyboard (array of rows)
 `[;,`Y # Interleave with `[;,`
 ∑ # Concatenate all of that
 :ǔL· # Shift each character 1 right relative to this in the input.

Python 3, 61 bytes

lambda s:s.translate('p?ml ??'*14+'vxswdfguhjknbio?earycqzt')

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Explanation

A naive implementation with str.translate would use the following translation table:

???????????????????????????????? ???????????m??????????????l???????????????????????????????p??????vxswdfguhjknbio?earycqzt

To optimize for size, notice that the characters ' mlp' all have different positions, modulo 7. As such, we can replace the first 98 characters of the table with 'p?ml ??'*14. The rest of the table is the same.

• \$\begingroup\$ Can you please explain this code? How does translate works without maketrans? \$\endgroup\$

  Diana Andrei

  – Diana Andrei

  2021年07月09日 01:17:22 +00:00

  Commented Jul 9, 2021 at 1:17
• \$\begingroup\$ @DianaAndrei If given a string as an argument, translate will replace the nth ASCII character with the character at the nth position of the string. I believe it uses __getitem__ internally, which explains this behavior. \$\endgroup\$

  dingledooper

  – dingledooper

  2021年07月09日 03:15:00 +00:00

  Commented Jul 9, 2021 at 3:15

Bash, 34 bytes

tr snvfrghjokl\;,mp[wtdyibecux a-z

Try it online! Using bash because I don't know how to score this as a tr answer.

Haskell, 65 bytes

a#(c:d)|a==c=d!!0|1>0=a#d
map(#",mnbvcxz;lkjhgfdsa[poiuytrewq ")

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(#) takes a character and a string and returns the character after the first match in the string. Our implementation then just maps this across the string with ,mnbvcxz;lkjhgfdsa[poiuytrewq as the preset string.

C# (Visual C# Interactive Compiler), 64 bytes

x=>x.Select(t=>" mlpvxswdfguhjknbio?earycqzt"[t%94%88%57%43%32])

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• \$\begingroup\$ What is the logic behind? Could you explain steps/way how you figure out the index modulo numbers ? \$\endgroup\$

  Soner from The Ottoman Empire

  – Soner from The Ottoman Empire

  2021年07月04日 02:37:06 +00:00

  Commented Jul 4, 2021 at 2:37

JavaScript (ES6), 66 bytes

I/O format: array of characters.

a=>a.map(c=>(S=" ,mnbvcxz;lkjhgfdsa[poiuytrewq")[S.indexOf(c)+1])

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JavaScript (ES6), 57 bytes

If taking an array of ASCII codes as input and returning an array of characters is acceptable, we can do:

b=>b.map(c=>"rjbwgtvacnofh_spzleykidumx_q "[c*19%116%30])

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• 1
  \$\begingroup\$ Could you explain steps/way how you figure out index modulo numbers? And the logic behind? \$\endgroup\$

  Soner from The Ottoman Empire

  – Soner from The Ottoman Empire

  2021年07月04日 02:38:58 +00:00

  Commented Jul 4, 2021 at 2:38

Ruby -p, 40+1 bytes

$_.tr!"snvfrghjokl;,mp[wtdyibecux","a-z"

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C (gcc), 79 bytes

I combined the source and destination strings so that I can take the character after the match. By inverting the list of characters, I could avoid -1 indexes and having to special-case spaces.

f(char*s){for(;*s;putchar(strchr(",mnbvcxz;lkjhgfdsa[poiuytrewq ",*s++)[1]));}

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Retina 0.8.2, 36 bytes

T`snvfrg\hj\ok\l;,m\p[\wt\dyibecux`l

Try it online! Link includes test cases. Explanation: Simply a transliteration, although Retina's built-in classes need to be escaped on the source string (obviously the built-in class l is desired on the target string).

Alternative solution, also 36 bytes:

T`\wertyuio-p[as\df-hj-l;zxcvbnm,`qo

Try it online! Link includes test cases. Transliterates the letters in keyboard order. This costs bytes because a and z have to be included in the source list and q in the destination list but then bytes can be saved by using character ranges to avoid quoting the o, p, h and l character classes.

Japt -m, 29 bytes

;D+S ·¬v gD·mÅí"[;,"¬'+ ¬v bU

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; -> use second set of predef. Vars
-m flag -> map input by the program (U)->
 g - take from 
D+S·¬v [ QWERTY +' ' split on (\n),rejoined, to lowercase ]
Dxxx bU - at index of input in[WERTY..]
D· - QWERTY split on \n
mÅ - remove 1st char on each
í - pair with :
"[;,"¬ - ..splitted
'+ - and join
¬v - join all and to lowercase

Haskell, 59 bytes

mapM(`lookup`(zip<*>tail)",mnbvcxz;lkjhgfdsa[poiuytrewq ")

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A function String -> Maybe String; it maps "s gom" to Just "a fin".

Common Lisp, 102 bytes

(defun f(i &aux(s",mnbvcxz;lkjhgfdsa[poiuytrewq "))(map'string(lambda(c)(elt s(1+(position c s))))i))

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Test cases included in TIO.

Excel, 93 bytes

=CONCAT(IFERROR(CHAR(FIND(MID(A1,SEQUENCE(LEN(A1)),1),"snvfrghjokl;,mp[wtdyibecux")+96)," "))

Link to Spreadsheet

PHP, 80 bytes

str_replace($a=str_split('wertyuiop[asdfghjkl;yxcvbnm,'),[-1=>'q']+$a,$argv[1]);

Avoids string repetition and double str_split().

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Charcoal, 36 bytes

≔"⧴3�7Rrηs⟲θ]+L÷↗1T"[〜↓TφF"η⭆S§η⊕⌕ηι

Try it online! Link is to verbose version of code. Explanation: Port of @ErikF's C answer, except putting the spaces at the beginning because that compresses better.

≔"⧴3�7Rrηs⟲θ]+L÷↗1T"[〜↓TφF"η

Assign the compressed string ,mnbvcxz;lkjhgfdsa[poiuytrewq to a variable.

⭆S§η⊕⌕ηι

Find each input character in the string and print the character that follows it.

Perl 5, 57 bytes

s/./",mnbvcxz;lkjhgfdsa[poiuytrewq "=~m|\Q$&\E(.)|;1ドル/ge

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s/. #replace one char at a time from input
 /
 ",mnbvcxz;lkjhgfdsa[poiuytrewq " #...with its next char in this string
 =~ m| \Q$&\E (.)|x; #found by searching for current char in $&
 #which must be escaped by \Q and \E
 #since [ has a special meaning in regexes.
 1ドル #Return next char captured into 1ドル by (.) 
 /gex #g = global search: all chars
 #e = treat replacement string as eval code
 #x = allow white-space, improve readability

R, (削除) 68 (削除ここまで) 55 bytes

function(x)chartr("snvfrghjokl;,mp[wtdyibecux","a-z",x)

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Abusing laconic Ranges are supported in the specifications in chartr documentation (forced to work by try and error).

Inspired by @Neil's answer.

Pyth, (削除) 45 (削除ここまで) 35 bytes

.rQ"[poiuytrewq;lkjhgfdsa,mnbvcxz 

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sm?gJtxK.",zcVÖzùwÔ\"
Ã?4‰ØÝ”gR133"dZ@KJ\ Q

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*Edit: Improved solution is rather boring...
"[poiuytrewq;lkjhgfdsa,mnbvcxz is a string of every possible char followed by the char it's meant to be (i.e. ytrewq) with two spaces on the end (space is meant to be space);

This is all surrounded with .r which will translate each element of Q(Input) into the next element.

Previous solution
Haven't golfed in a while so this feels pretttty rusty...

Maps through qwerty string, shifting char to the left unless it's a space.

05AB1E, 13 bytes

žV€¦...[;,øSžW‡

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Explanation:

žV # Push builtin ["qwertyuiop","asdfghjkl","zxcvbnm"]
 €¦ # Remove the first character from each: ["wertyuiop","sdfghjkl","xcvbnm"]
 ...[;,ø # Zip/transpose with string "[;,":
 # [["wertyuiop","["],["sdfghjkl",";"],["xcvbnm",","]]
 S # Convert it to a flattened list of characters: 
 # ["w","e","r","t","y","u","i","o","p","[","s","d","f","g","h","j","k",
 # "l",";","x","c","v","b","n","m",","]
 žW # Push builtin "qwertyuiopasdfghjklzxcvbnm"
 ‡ # Transliterate all characters in the (implicit) input
 # (after which the result is output implicitly)

sed has a command specifically for this that I rarely get to use, so:

sed, 56 bytes

y/wertyuiop[sdfghjkl;xcvbnm,/qwertyuiopasdfghjklzxcvbnm/

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the 'y' command maps letters matching the first string to their position in the second

Uiua, 39 characters/45 bytes

⊏+1⊸⊗:" ,mnbvcxz;lkjhgfdsa[poiuytrewq"

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" ,mnbvcxz;lkjhgfdsa[poiuytrewq" is the entire keyboard, plus the shifted characters, plus two spaces, written in reverse (explained later). This string is pushed to the stack first, then:

 : # Flip the top two stack values, placing the keyboard string under the input
 ⊸⊗ # Replace characters in the input with their indices in the keyboard string,
 # but keep the keyboard string underneath on the stack
 +1 # Add 1 to all the indices, shifting left in the keyboard string
⊏ # Select all the indices in the resulting array from the keyboard string

⊗ searches the haystack string from the left, which means that spaces will get replaced with the index of the first space, meaning the index must be +1'd to shift it to the second space. For this reason, the rest of the keyboard string is written in reverse so that +1 acts as a leftward shift.

PHP, (削除) 186 (削除ここまで) 114 Bytes

$W=str_split(",mnbvcxz;lkjhgfdsa[poiuytrewq");for(;$c=$argv[1][$p++];)echo($c!==" ")?$W[array_flip($W)[$c]+1]:" ";

Try it online! Definitely not the shortest answer on here, but I'm not sure how I could handle this in PHP without using a big array. Any input would be greatly appreciated!

-72 bytes by changing a large keyed array into one small one. Just iterates over every character, find it in the array, then prints the next element in the array.

• \$\begingroup\$ 102 Bytes Not sure why you went with iterating when str_replace does the job very well \$\endgroup\$

  Tofandel

  – Tofandel

  2021年07月03日 18:05:58 +00:00

  Commented Jul 3, 2021 at 18:05

Go, 138 bytes

import."strings"
func f(s string)(o string){M:=`,mnbvcxz;lkjhgfdsa[poiuytrewq `
for _,r:=range s{i:=IndexRune(M,r)+1
o+=M[i:i+1]}
return}

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Go, 142 bytes

import."strings"
func f(s string)string{M:=`,mnbvcxz;lkjhgfdsa[poiuytrewq `
return Map(func(r rune)rune{return rune(M[IndexRune(M,r)+1])},s)}

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Both solutions use the same keyboard mapping found by other users. Amazing how the solution using the manual loop is only 4 bytes shorter than using the stdlib approach.

• code-golf
• string