Equilateral Triangle, Straight Line and Tangent Circles: What Is This About?
A Mathematical Droodle
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Copyright © 1996-2018 Alexander Bogomolny
The applet purports to suggest the following sangaku [Temple Geometry, p. 25, #2.1.11]:
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(This is a 1885 Sangaku from the Fukusima prefecture whose tablet has disappeared long ago.)
Let K, L, M, N, S, T be the points of tangency as shown in the applet and s be the common length of the sides of ΔABC. Denote
y = BN = BL.
Then
s - y = CN = CT.
Two external tangents to a pair of circles are equal: KL = ST which tells us that
implying
But triangles OAK and QBL are both 30°-60°-90°. Therefore, ra = √3·x and rb = √3·y such that
References
H. Fukagawa, D. Pedoe, Japanese Temple Geometry Problems, The Charles Babbage Research Center, Winnipeg, 1989
Write to:
Charles Babbage Research Center
P.O. Box 272, St. Norbert Postal Station
Winnipeg, MB
Canada R3V 1L6
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Copyright © 1996-2018 Alexander Bogomolny
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