\label{eq2}\begin{array}{@{}l} \displaystyle \left[{\left[{x = -{\frac{a}{b}}}, \:{y = 0}, \:{z = -{\frac{{a}^{2}}{{b}^{2}}}}\right]}, \: \right. \ \ \displaystyle \left.{ \begin{array}{@{}l} \displaystyle \left[{x ={\frac{{{z}^{3}}+{2 \ b \ {{z}^{2}}}+{{{b}^{2}}\ z}- a}{b}}}, \:{y ={z + b}}, \: \right. \ \ \displaystyle \left.{ \begin{array}{@{}l} \displaystyle {{{z}^{6}}+{4 \ b \ {{z}^{5}}}+{6 \ {{b}^{2}}\ {{z}^{4}}}+{{\left({4 \ {{b}^{3}}}-{2 \ a}\right)}\ {{z}^{3}}}+{{\left({{b}^{4}}-{4 \ a \ b}\right)}\ {{z}^{2}}}-{2 \ a \ {{b}^{2}}\ z}-{{b}^{3}}+{{a}^{2}}}= \ \ \displaystyle 0
(2)