Edit detail for #178 Linear Agebra problem revision 1 of 1

1
Editor:
Time: 2007年11月17日 22:03:09 GMT-8
Note: Same as bug #170

changed:
-
This doesn't work:
\begin{axiom}
L := [ A = 2*P1+P2, B = 2*P2+P1, C = 2*Q1+Q2, D = 2*Q2+Q1]
solve(L, [P1,P2])
\end{axiom}
But it should, observe this:
\begin{axiom}
SA:=solve([L.1,L.2],[P1,P2])
SB:=solve([L.3,L.4],[Q1,Q2])
\end{axiom}
First two equationa do not depend on $Q_i,ドル the later two don't depend on $P_i$.
Now check it again the initial set:
\begin{axiom}
S:=[SA.1.1,SA.1.2,SB.1.1,SB.1.2]
map(x+->eval(x,S),L)
\end{axiom}
From kratt6 Tue Jun 21 02:20:21 -0500 2005
From: kratt6
Date: 2005年6月21日 02:20:21 -0500
Subject: Same as bug #170
Message-ID: <20050621022021-0500@page.axiom-developer.org>
Status: open => duplicate 


Submitted by : (unknown) at: 2007年11月17日T22:03:09-08:00 (18 years ago)
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Axiom Version :
Category : Severity : Status :
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This doesn't work:

fricas
(1) -> L := [ A = 2*P1+P2, B = 2*P2+P1, C = 2*Q1+Q2, D = 2*Q2+Q1]
Type: List(Equation(Polynomial(Integer)))
fricas
solve(L, [P1,P2])
Type: List(List(Equation(Fraction(Polynomial(Integer)))))

But it should, observe this:

fricas
SA:=solve([L.1,L.2],[P1,P2])
Type: List(List(Equation(Fraction(Polynomial(Integer)))))
fricas
SB:=solve([L.3,L.4],[Q1,Q2])
Type: List(List(Equation(Fraction(Polynomial(Integer)))))

First two equationa do not depend on Q_i, the later two don't depend on P_i. Now check it again the initial set:

fricas
S:=[SA.1.1,SA.1.2,SB.1.1,SB.1.2]
Type: List(Equation(Fraction(Polynomial(Integer))))
fricas
map(x+->eval(x,S),L)
Type: List(Equation(Expression(Integer)))

Status: open => duplicate

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