changed: - This doesn't work: \begin{axiom} L := [ A = 2*P1+P2, B = 2*P2+P1, C = 2*Q1+Q2, D = 2*Q2+Q1] solve(L, [P1,P2]) \end{axiom} But it should, observe this: \begin{axiom} SA:=solve([L.1,L.2],[P1,P2]) SB:=solve([L.3,L.4],[Q1,Q2]) \end{axiom} First two equationa do not depend on $Q_i,ドル the later two don't depend on $P_i$. Now check it again the initial set: \begin{axiom} S:=[SA.1.1,SA.1.2,SB.1.1,SB.1.2] map(x+->eval(x,S),L) \end{axiom} From kratt6 Tue Jun 21 02:20:21 -0500 2005 From: kratt6 Date: 2005年6月21日 02:20:21 -0500 Subject: Same as bug #170 Message-ID: <20050621022021-0500@page.axiom-developer.org> Status: open => duplicate
This doesn't work:
(1) -> L := [ A = 2*P1+P2,B = 2*P2+P1, C = 2*Q1+Q2, D = 2*Q2+Q1]
solve(L,[P1, P2])
But it should, observe this:
SA:=solve([L.1,L.2], [P1, P2])
SB:=solve([L.3,L.4], [Q1, Q2])
First two equationa do not depend on Q_i, the later two don't depend on P_i. Now check it again the initial set:
S:=[SA.1.1,SA.1.2, SB.1.1, SB.1.2]
map(x+->eval(x,S), L)