std::variant<Types...>::variant
constexpr variant( T&& t ) noexcept(/* see below */);
class... Args >
constexpr explicit variant( std::in_place_type_t <T>,
class U,
class... Args >
constexpr explicit variant( std::in_place_type_t <T>,
std::initializer_list <U> il,
class... Args >
constexpr explicit variant( std::in_place_index_t <I>,
class U,
class... Args >
constexpr explicit variant( std::in_place_index_t <I>,
std::initializer_list <U> il,
Constructs a new variant object.
variant holding the value-initialized value of the first alternative (index() is zero).
- This constructor is constexpr if and only if the value initialization of the alternative type
T_0would satisfy the requirements for a constexpr function. - This overload participates in overload resolution only if std::is_default_constructible_v <T_0> is true.
variant holding the same alternative as other and direct-initializes the contained value with *std::get_if <other.index()>(std::addressof (other)). Otherwise, initializes a valueless_by_exception variant.
- This constructor is defined as deleted unless std::is_copy_constructible_v <T_i> is true for all
T_iin Types.... - It is trivial if std::is_trivially_copy_constructible_v <T_i> is true for all
T_iin Types....
variant holding the same alternative as other and direct-initializes the contained value with std::move(*std::get_if <other.index()>(std::addressof (other))). Otherwise, initializes a valueless_by_exception variant.
- This overload participates in overload resolution only if std::is_move_constructible_v <T_i> is true for all
T_iin Types.... - It is trivial if std::is_trivially_move_constructible_v <T_i> is true for all
T_iin Types....
variant holding the alternative type T_j that would be selected by overload resolution for the expression F(std::forward <T>(t)) if there was an overload of imaginary function F(T_i) for each T_i in Types..., except that narrowing conversions aren't considered.
Formally:
- An overload F(T_i) is only considered if the declaration T_i x[] = { std::forward <T>(t) }; is valid for some invented variable
x.
- An overload F(T_i) is only considered if the declaration T_i x[] = { std::forward <T>(t) }; is valid for some invented variable
- This overload participates in overload resolution only if
- sizeof...(Types) > 0,
- std::decay_t <T>(until C++20)std::remove_cvref_t <T>(since C++20) is neither the same type as
variant, nor a specialization of std::in_place_type_t , nor a specialization of std::in_place_index_t , - std::is_constructible_v <T_j, T> is true,
- and the expression F(std::forward <T>(t)) (with F being the above-mentioned set of imaginary functions) is well formed.
- This constructor is a constexpr constructor if
T_j's selected constructor is a constexpr constructor.
std::variant <std::string > v("abc"); // OK std::variant <std::string, std::string > w("abc"); // ill-formed std::variant <std::string, const char*> x("abc"); // OK, chooses const char* std::variant <std::string, bool> y("abc"); // OK, chooses string; bool is not a candidate std::variant <float, long, double> z = 0; // OK, holds long // float and double are not candidates
variant with the specified alternative T and initializes the contained value with the arguments std::forward <Args>(args)....
- If
T's selected constructor is a constexpr constructor, this constructor is also a constexpr constructor. - This overload participates in overload resolution only if there is exactly one occurrence of
Tin Types... and std::is_constructible_v <T, Args...> is true.
variant with the specified alternative T and initializes the contained value with the arguments il, std::forward <Args>(args)....
- If
T's selected constructor is a constexpr constructor, this constructor is also a constexpr constructor. - This overload participates in overload resolution only if there is exactly one occurrence of
Tin Types... and std::is_constructible_v <T, initializer_list<U>&, Args...> is true.
variant with the alternative T_i specified by the index I and initializes the contained value with the arguments std::forward <Args>(args)....
- If
T_i's selected constructor is a constexpr constructor, this constructor is also a constexpr constructor. - This overload participates in overload resolution only if I < sizeof...(Types) and std::is_constructible_v <T_i, Args...> is true.
variant with the alternative T_i specified by the index I and initializes the contained value with the arguments il, std::forward <Args>(args)....
- If
T_i's selected constructor is a constexpr constructor, this constructor is also a constexpr constructor. - This overload participates in overload resolution only if I < sizeof...(Types) and std::is_constructible_v <T_i, std::initializer_list <U>&, Args...> is true.
[edit] Parameters
variant object whose contained value to copy/move
[edit] Exceptions
T_i in Types....T_i in Types.... T_j. [edit] Notes
MSVC STL initially treated P0608R3 as a change in C++20. As of VS 2022 17.12, MSVC STL also treats P0608R3 as a defect report against C++17.
[edit] Example
#include <cassert> #include <iostream> #include <string> #include <variant> #include <vector> using vector_t = std::vector <int>; auto& operator<<(auto& out, const vector_t& v) { out << "{ "; for (int e : v) out << e << ' '; return out << '}'; } int main() { // value-initializes first alternative std::variant <int, std::string > var0; assert (std::holds_alternative <int>(var0) and var0.index() == 0 and std::get<int>(var0) == 0); // initializes first alternative with std::string{"STR"}; std::variant <std::string, int> var1{"STR"}; assert (var1.index() == 0); std::cout << "1) " << std::get<std::string >(var1) << '\n'; // initializes second alternative with int == 42; std::variant <std::string, int> var2{42}; assert (std::holds_alternative <int>(var2)); std::cout << "2) " << std::get<int>(var2) << '\n'; // initializes first alternative with std::string{4, 'A'}; std::variant <std::string, vector_t, float> var3 { std::in_place_type <std::string >, 4, 'A' }; assert (var3.index() == 0); std::cout << "3) " << std::get<std::string >(var3) << '\n'; // initializes second alternative with std::vector{1,2,3,4,5}; std::variant <std::string, vector_t, char> var4 { std::in_place_type <vector_t>, {1, 2, 3, 4, 5} }; assert (var4.index() == 1); std::cout << "4) " << std::get<vector_t>(var4) << '\n'; // initializes first alternative with std::string{"ABCDE", 3}; std::variant <std::string, vector_t, bool> var5 {std::in_place_index <0>, "ABCDE", 3}; assert (var5.index() == 0); std::cout << "5) " << std::get<std::string >(var5) << '\n'; // initializes second alternative with std::vector(4, 42); std::variant <std::string, vector_t, char> var6 {std::in_place_index <1>, 4, 42}; assert (std::holds_alternative <vector_t>(var6)); std::cout << "6) " << std::get<vector_t>(var6) << '\n'; }
Output:
1) STR
2) 42
3) AAAA
4) { 1 2 3 4 5 }
5) ABC
6) { 42 42 42 42 }[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 2901 | C++17 | allocator-aware constructors provided butvariant can't properly support allocators
|
constructors removed |
| P0739R0 | C++17 | converting constructor template interacts poorly with class template argument deduction |
constraint added |
| LWG 3024 | C++17 | copy constructor doesn't participate in overload resolution if any member type is not copyable |
defined as deleted instead |
| P0602R4 | C++17 | copy/move constructors may not be trivial even if underlying constructors are trivial |
required to propagate triviality |
| P0608R3 | C++17 | converting constructor blindly assembles an overload set, leading to unintended conversions |
narrowing and boolean conversions not considered |
| P1957R2 | C++17 | converting constructor for bool did not allow implicit conversion |
Pointer to bool conversion is narrowing and converting constructor has no exception for bool |