deduction guides for std::packaged_task
 
 
 From cppreference.com
 
 
 < cpp | thread | packaged task 
 
 
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std::packaged_task 
 
 Member functions
 Getting the result
 Execution
 Non-member functions
 Helper classes
(until C++17)
 Deduction guides(C++17)
Defined in header 
 
 
<future> 
 template< class R, class... Args > 
packaged_task( R(*)(Args...) ) -> packaged_task<R(Args...)>;
 (1) 
 (since C++17) 
packaged_task( R(*)(Args...) ) -> packaged_task<R(Args...)>;
template< class F >
packaged_task( F ) -> packaged_task</*see below*/>;
 (2) 
 (since C++17) 
packaged_task( F ) -> packaged_task</*see below*/>;
template< class F >
packaged_task( F ) -> packaged_task</*see below*/>;
 (3) 
 (since C++23) 
packaged_task( F ) -> packaged_task</*see below*/>;
template< class F >
packaged_task( F ) -> packaged_task</*see below*/>;
 (4) 
 (since C++23) 
packaged_task( F ) -> packaged_task</*see below*/>;
2) This overload participates in overload resolution only if &F::operator() is well-formed when treated as an unevaluated operand and decltype(&F::operator()) is of the form R(G::*)(A...) (optionally cv-qualified, optionally noexcept, optionally lvalue reference qualified). The deduced type is std::packaged_task <R(A...)>.
3) This overload participates in overload resolution only if &F::operator() is well-formed when treated as an unevaluated operand and F::operator() is an explicit object parameter function whose type is of form R(G, A...) or R(G, A...) noexcept. The deduced type is std::packaged_task <R(A...)>.
4) This overload participates in overload resolution only if &F::operator() is well-formed when treated as an unevaluated operand and F::operator() is a static member function whose type is of form R(A...) or R(A...) noexcept. The deduced type is std::packaged_task <R(A...)>.
[edit] Notes
These deduction guides do not allow deduction from a function with ellipsis parameter, and the ... in the types is always treated as a pack expansion.
[edit] Example
Run this code
#include <future> int func(double) { return 0; } int main() { std::packaged_task f{func}; // deduces packaged_task<int(double)> int i = 5; std::packaged_task g = [&](double) { return i; }; // => packaged_task<int(double)> }