std::filesystem::operator/(std::filesystem::path)
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< cpp | filesystem | path
C++
Feature test macros (C++20)
Concepts library (C++20)
Metaprogramming library (C++11)
Ranges library (C++20)
Filesystem library (C++17)
Concurrency support library (C++11)
Execution control library (C++26)
Filesystem library
std::filesystem::path
Path decomposition Non-member functions
Helper classes
(until C++20)(until C++20)(until C++20)(until C++20)(until C++20)(C++20)
(C++26)
friend path operator/( const path& lhs, const path& rhs );
(since C++17)
Concatenates two path components using the preferred directory separator if appropriate (see operator/= for details).
Effectively returns path(lhs) /= rhs.
This function is not visible to ordinary unqualified or qualified lookup, and can only be found by argument-dependent lookup when std::filesystem::path is an associated class of the arguments. This prevents undesirable conversions in the presence of a using namespace std::filesystem; using-directive.
[edit] Parameters
lhs, rhs
-
paths to concatenate
[edit] Return value
The result of path concatenation.
[edit] Example
Run this code
#include <filesystem> #include <iostream> int main() { # if defined(_WIN32) // see e.g. stackoverflow.com/questions/142508 std::filesystem::path p = "C:"; std::cout << R"("C:\" / "Users" / "batman" == )" << p / "Users" / "batman" << '\n'; # else // __linux__ etc std::filesystem::path p = "/home"; std::cout << R"("/home" / "tux" / ".fonts" ==)" << p / "tux" / ".fonts" << '\n'; # endif }
Possible output:
Windows specific output: "C:" / "Users" / "batman" == "C:Users\\batman" Linux etc specific output: "/home" / "tux" / ".fonts" == "/home/tux/.fonts"
[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 3065 | C++17 | allowed concatenating everything convertible to path in the presence of a using-directive
|
made hidden friend |