std::function_ref::operator=
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std::function_ref
function_ref::operator=
constexpr function_ref& operator=( const function_ref& ) noexcept = default;
(1)
(since C++26)
template< class T >
constexpr function_ref& operator=( T ) = delete;
(2)
(since C++26)
constexpr function_ref& operator=( T ) = delete;
1) Copy assignment operator is explicitly-defaulted.
std::function_ref satisfies copyable and TriviallyCopyable. This defaulted assignment operator performs a shallow copy of the stored thunk-ptr and bound-entity .2) User-defined assignment operator is explicitly-deleted if T is not the same type as
std::function_ref, std::is_pointer_v <T> is false, and T is not a specialization of std::nontype_t. This overload participates in overload resolution only if the constraints are satisfied in the conditions above.[edit] Return value
*this