std::chrono::year::operator+=, std::chrono::year::operator-=
From cppreference.com
 
 
 
 
 
 C++ 
 Feature test macros (C++20)
 Concepts library (C++20)
 Metaprogramming library (C++11)
 Ranges library (C++20)
 Filesystem library (C++17)
 Concurrency support library (C++11)
 Execution control library (C++26)
Date and time library 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
(C++11)
(C++20)
  (C++20)
(C++11)
(C++11)
(C++11)
(C++20)
(C++20)
(C++20)
(C++11)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
  (C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)
(C++20)
(C++20)
(C++20)
(C++20)(C++20)(C++20)(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
(C++20)
std::chrono::year 
 
 
 Member functions
year::operator+=year::operator-=
 Nonmember functions
 Helper classes
(C++26)
constexpr std::chrono::year & operator+=( const std::chrono::years & y ) noexcept;
 (1) 
 (since C++20) 
constexpr std::chrono::year & operator-=( const std::chrono::years & y ) noexcept;
 (2) 
 (since C++20) 
Adds or subtracts y.count() years from the year value.
1) Equivalent to *this = *this + y;.
2) Equivalent to *this = *this - y;.
Contents
[edit] Return value
A reference to this year after modification.
[edit] Notes
If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { using namespace std::literals::chrono_literals; std::cout << std::boolalpha ; std::chrono::year y{2020}; y += std::chrono::years (12); std::cout << (y == 2032y) << ' '; y -= std::chrono::years (33); std::cout << (y == 1999y) << '\n'; }
Output:
true true