std::chrono::abs(std::chrono::duration)
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std::chrono::duration 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
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abs
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Defined in header 
 
 
<chrono> 
 template< class Rep, class Period >
constexpr std::chrono::duration <Rep, Period> abs( std::chrono::duration <Rep, Period> d );
 
 (since C++17) 
constexpr std::chrono::duration <Rep, Period> abs( std::chrono::duration <Rep, Period> d );
Returns the absolute value of the duration d. Specifically, if d >= d.zero(), return d, otherwise return -d.
The function does not participate in the overload resolution unless std::numeric_limits <Rep>::is_signed is true.
[edit] Parameters
 d
 -
 duration
[edit] Return value
Absolute value of d.
[edit] Possible implementation
template<class Rep, class Period, class = std::enable_if_t <std::numeric_limits <Rep>::is_signed>> constexpr std::chrono::duration <Rep, Period> abs(std::chrono::duration <Rep, Period> d) { return d >= d.zero() ? +d : -d; }
[edit] Example
Run this code
#include <chrono> #include <iostream> int main() { using namespace std::chrono; static_assert(abs(-42s) == std::chrono::abs(42s)); std::cout << "abs(+3min) = " << abs(3min).count() << '\n' << "abs(-3min) = " << abs(-3min).count() << '\n'; }
Output:
abs(+3min) = 3 abs(-3min) = 3