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std::identity

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< cpp‎ | utility‎ | functional
 
 
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Identity function object
identity
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Defined in header <functional>
struct identity;
(since C++20)

std::identity is a function object type whose operator() returns its argument unchanged.

[edit] Member types

Type Definition
is_transparent unspecified

[edit] Member functions

operator()
returns the argument unchanged
(public member function)

std::identity::operator()

template< class T >
constexpr T&& operator()( T&& t ) const noexcept;

Returns std::forward <T>(t).

Parameters

t - argument to return

Return value

std::forward <T>(t).

[edit] Notes

std::identity serves as the default projection in constrained algorithms. Its direct usage is usually not needed.

[edit] Example

Run this code
#include <algorithm>
#include <functional>
#include <iostream>
#include <ranges>
#include <string>
 
struct Pair
{
 int n;
 std::string s;
 friend std::ostream & operator<<(std::ostream & os, const Pair& p)
 {
 return os << '{' << p.n << ", " << p.s << '}';
 }
};
 
// A range-printer that can print projected (modified) elements of a range.
template<std::ranges::input_range R,
 typename Projection = std::identity> //<- Notice the default projection
void print(std::string_view const rem, R&& range, Projection projection = {})
{
 std::cout << rem << '{';
 std::ranges::for_each (
 range,
 [O = 0](const auto& o) mutable { std::cout << (O++ ? ", " : "") << o; },
 projection
 );
 std::cout << "}\n";
}
 
int main()
{
 const auto v = {Pair{1, "one"}, {2, "two"}, {3, "three"}};
 
 print("Print using std::identity as a projection: ", v);
 print("Project the Pair::n: ", v, &Pair::n);
 print("Project the Pair::s: ", v, &Pair::s);
 print("Print using custom closure as a projection: ", v,
 [](Pair const& p) { return std::to_string (p.n) + ':' + p.s; });
}

Output:

Print using std::identity as a projection: {{1, one}, {2, two}, {3, three}}
Project the Pair::n: {1, 2, 3}
Project the Pair::s: {one, two, three}
Print using custom closure as a projection: {1:one, 2:two, 3:three}

[edit] See also

returns the type argument unchanged
(class template) [edit]
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