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LAST UPDATED: NOVEMBER 1, 2020

C++ Find Minimum Element in a Rotated Sorted Vector Program

Hello Everyone!

In this tutorial, we will demonstrate the logic of Finding the Minimum Element in a Rotated Sorted Vector, in the C++ programming language.

What is a Rotated Sorted Vector?

A Rotated Sorted Vector is a sorted vector rotated at some pivot element unknown to you beforehand.

Example: [4,5,6,7,0,1,2] is one of the rotated sorted vector for the sorted vector [0,1,2,4,5,6,7].

For a better understanding of its implementation, refer to the well-commented CPP code given below.

Code:

#include <iostream>
#include <bits/stdc++.h>
using namespace std;
int findMin(vector<int> &m)
{
 int i;
 int n = m.size();
 for (i = 0; i < n; i++)
 {
 if (i == 0)
 {
 if (m[i] < m[n - 1] && m[i] < m[1])
 break;
 }
 else
 {
 if (m[i] < m[i - 1] && m[i] < m[(i + 1) % n])
 break;
 }
 }
 return m[i % n];
}
int main()
{
 cout << "\n\nWelcome to Studytonight :-)\n\n\n";
 cout << " ===== Program to find the Minimum element in a rotated Sorted Vector, in CPP ===== \n\n\n";
 cout << " ===== Logic: The minimum element will have larger number on both right and left of it. ===== \n\n\n";
 //initializing vector with the following elements
 vector<int> v = {4, 5, 6, 7, 1, 3, 2};
 int n = v.size();
 int mini = 0;
 cout << "The elements of the given vector is : ";
 for (int i = 0; i < n; i++)
 {
 cout << v[i] << " ";
 }
 mini = findMin(v);
 cout << "\n\nThe Minimum element in the given vector is: " << mini;
 cout << "\n\n\n";
 return 0;
}

Output:

C++ rotated sorted vector

We hope that this post helped you develop a better understanding of the concept of finding a minimum element in the rotated sorted vector and its implementation in CPP. For any query, feel free to reach out to us via the comments section down below.

Keep Learning : )



About the author:
Nikita Pandey is a talented author and expert in programming languages such as C, C++, and Java. Her writing is informative, engaging, and offers practical insights and tips for programmers at all levels.

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