题目:输入一个奇数,然后判断最少几个 9 除于该数的结果为整数。
程序分析:999999 / 13 = 76923。
程序源代码:
以上实例输出结果为:
输入一个数字: 13 6 个 9 可以被 13 整除 : 999999 999999 / 13 = 76923
叮咚
a12***[email protected]
参考解法:
#!/usr/bin/python
# -*- coding: UTF-8 -*-
b=input('input a number:\n')
a=9
n=1
while (1):
if a%b==0:
break
else:
a=a*10+9
n=n+1
print '%d 个 9 除于 %d 为整数' % (n,b)
叮咚
a12***[email protected]
du_solong
157***[email protected]
参考方法:
# -*- coding: utf-8 -*-
"""
Created on Fri Jun 30 17:08:43 2017
@author: zhangch
"""
"""
输入一个正整数,然后判断最少几个 9 除于该数的结果为整数。
"""
if __name__ == "__main__":
i = int(raw_input('input a number:'))
sum = 9
while sum % i != 0:
sum = sum * 10 + 9
print sumdu_solong
157***[email protected]
colinshi
col***[email protected]
参考方法:
#!/usr/bin/python3
# -*- coding: UTF-8 -*-
def monkey():
a=int(input('输入一个数字:\n'))
b=9
i=1
while True:
if b > a and b%a==0:
print('需要{}个9'.format(i))
break
else:
b = b*10+9
i+=1
if __name__ == '__main__':
monkey()colinshi
col***[email protected]
Gagarin
fsi***[email protected]
参考方法:
# -*- coding: utf-8 -*-
if __name__=='__main__':
n=int(raw_input('输入数字:\n'))
s=9
while True:
if s%n==0:
l = len(str(s))
print '%d 个 9 除于 %d 为整数' % (l,n)
break
else:
st= str(s)+'9'
s=int(st)
Gagarin
fsi***[email protected]
pjdssjdcr
735***[email protected]
参考方法:
# -*- coding: utf-8 -*-
n = int(raw_input("n:"))
j = 1
sum = 0
for i in range(20):
sum += 9*j
if (sum%n == 0):
print sum,sum/13
break
else:
j = j*10
pjdssjdcr
735***[email protected]