题目:八进制转换为十进制
程序分析:无。
以上实例输出结果为:
input a octal number: 122 82
hello world
hel***[email protected]
Python3 参考方法:
#!/usr/bin/python3
def f8to10(num):
print("8进制数:", num)
l = str(num)
length = len(l)
sum = 0
for i in range(length):
sum += 8 ** i * int(l[length-1-i])
print("转成10进制数为:",sum)
f8to10(122)
hello world
hel***[email protected]
......
abc***[email protected]
参考方法:
#!/usr/bin/python
# -*- coding: UTF-8 -*-
if __name__ == '__main__':
n = s = 0
L = []
n = raw_input("请输入一个八进制数: \n")
for i in range(len(n)):
L.append(n[i])
L.reverse()
for i in range(len(n)):
s = s + int(L[i])*(8**i)
print s......
abc***[email protected]
ray
117***[email protected]
参考方法:
#!/usr/bin/python
# -*- coding: UTF-8 -*-
def batoshi(num):
count=0
j=len(num)-1
for each_ch in num:
count+=pow(8,j)*int(each_ch)
j-=1
return count
print(batoshi('122'))ray
117***[email protected]
薄荷可乐
r49***[email protected]
#coding=utf-8
n=raw_input('请输入一个八进制数:')
#使用列表推导式来写
lost=sum([int(n[-i])*8**(i-1) for i in range(1,len(n)+1)])
print '转换十进制数为:%s'%lost薄荷可乐
r49***[email protected]
shizi
ris***[email protected]
参考方法:
#coding=utf-8
n = reversed('122')
s = 0
for idx,i in enumerate(n):
s += int(i) * pow(8, idx)
print (s)shizi
ris***[email protected]