3 篇笔记 写笔记

1. #0

   小雨济苍生

   27d***163.com

   1

   参考方法:

   #!/usr/bin/python
   # -*- coding: UTF-8 -*-
   import re
   def judge(first,list):
    li=[]
    first = first.upper()
    for a in list:
    if re.match(first,a):
    li.append(a)
    if len(li)==1:
    print li[0]
    else:
    second=raw_input('请输入第二个字母:')
    for b in li:
    if re.match(first+second,b):
    print b
   list=['Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday']
   first=raw_input('请输入第一个字母:')
   judge(first,list)
   

   小雨济苍生

   27d***163.com

   9年前 (2017年06月02日)
2. #0

   ddo543

   zhu***[email protected]

   73

   Python3 测试实例:

   #!/usr/bin/python3
   weeklist = {'M': 'Monday','T': {'u': 'Tuesday','h':'Thursday'}, 'W': 'Wednesday', 'F':'Friday','S':{'a':'Saturday','u':'Sunday'}}
   sLetter1 = input("请输入首字母:")
   sLetter1 = sLetter1.upper()
   if (sLetter1 in ['T','S']):
    sLetter2 = input("请输入第二个字母:")
    print(weeklist[sLetter1][sLetter2])
   else:
    print(weeklist[sLetter1])
   

   ddo543

   zhu***[email protected]

   9年前 (2017年06月07日)
3. #0

   Think_dfrent

   iwa***[email protected]

   11

   Python3实例,使用递归函数实现,对字符相同的个数没有限制 :

   #!/usr/bin/env python3
   week=['Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday']
   def find(s,week):
    a = input("please input a letter\n")
    s=s+a
    #print(s) 
    result=[]
    for i in week:
    if i.startswith(s):
    result.append(i)
    #print (result) 
    if len(result)==1:
    return result
    else:
    return find(s,result)
   s=''
   print(find(s,week))

   Think_dfrent

   iwa***[email protected]

   9年前 (2017年06月19日)