array_sum

(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)

array_sum — 对数组中所有值求和

说明

function array_sum(array $array): int |float

array_sum() 将数组中的所有值相加,并返回结果。

参数

array: 输入的数组。

返回值

所有值的和以整数或浮点数的结果返回,array 为空时则返回 0。

更新日志

版本	说明
8.3.0	当 `array` 值不能转换为 int 或 float 时,现在会发出 `E_WARNING` 。之前会忽略 array 和 object ,而其它的值会转换为 int 。此外,现在也会转换定义了数字转换的对象(比如 GMP )而不是忽略它。

示例

示例 #1 array_sum() 例子

<?php
$a = array(2, 4, 6, 8);
echo "sum(a) = " . array_sum($a) . "\n";
$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4);
echo "sum(b) = " . array_sum($b) . "\n";
?>

以上示例会输出:

sum(a) = 20
sum(b) = 6.9

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用户贡献的备注 2 notes

down

rodrigo at adboosters dot com ¶

4 years ago

If you want to calculate the sum in multi-dimensional arrays:
<?php
function array_multisum(array $arr): float {
 $sum = array_sum($arr);
 foreach($arr as $child) {
 $sum += is_array($child) ? array_multisum($child) : 0;
 }
 return $sum;
}
?>

Example:
<?php
$data = 
[
 'a' => 5,
 'b' => 
 [
 'c' => 7, 
 'd' => 3
 ],
 'e' => 4,
 'f' => 
 [
 'g' => 6,
 'h' => 
 [
 'i' => 1,
 'j' => 2
 ]
 ]
];
echo array_multisum($data);
//output: 28
?>

down

harl at gmail dot com ¶

3 years ago

array_sum() doesn't "ignore strings if they are not convertible", it converts them to zero. array_product() does the same thing, where the difference between "ignoring" and "converting to zero" is much more obvious.