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is_a

(PHP 4 >= 4.2.0, PHP 5, PHP 7, PHP 8)

is_aVerifica si el objeto es de un cierto tipo o subtipo.

Descripción

function is_a(mixed $object_or_class, string $class, bool $allow_string = false ): bool

Determina si el object_or_class dado es del tipo de objeto clase, o tiene clase como uno de sus supertipos.

Parámetros

object_or_class

Un nombre de clase o una instancia de un objeto.

class

El nombre de la clase o de la interfaz.

allow_string

Si este argumento vale false , el nombre de la clase en forma de string en el argumento object_or_class no está permitido. Esto permite evitar la llamada al autoloader si la clase no existe.

Valores devueltos

Retorna true si object_or_class es del tipo de objeto clase, o tiene clase como uno de sus supertipos, false en caso contrario.

Ejemplos

Ejemplo #1 Ejemplo con is_a()

<?php
// Define una clase
class WidgetFactory
{
 var $oink = 'moo';
}
// Crea un nuevo objeto
$WF = new WidgetFactory();
if (is_a($WF, 'WidgetFactory')) {
 echo "sí, \$WF es siempre un objeto WidgetFactory\n";
}
?>

Ejemplo #2 Uso del operador instanceof

<?php
// definir una clase
class WidgetFactory
{
 var $oink = 'moo';
}
// crear un nuevo objeto
$WF = new WidgetFactory();
if ($WF instanceof WidgetFactory) {
 echo 'Sí, $WF es un WidgetFactory';
}
?>

Véase también

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User Contributed Notes 7 notes

up
75
Ronald Locke
9 years ago
Please note that you have to fully qualify the class name in the second parameter. 
A use statement will not resolve namespace dependencies in that is_a() function. 
<?php 
namespace foo\bar;
class A {};
class B extends A {};
?>

<?php
namespace har\var;
use foo\bar\A;
$foo = new foo\bar\B();
is_a($foo, 'A'); // returns false;
is_a($foo, 'foo\bar\A'); // returns true;
?>

Just adding that note here because all examples are without namespaces.
up
34
Aron Budinszky
14 years ago
Be careful! Starting in PHP 5.3.7 the behavior of is_a() has changed slightly: when calling is_a() with a first argument that is not an object, __autoload() is triggered!
In practice, this means that calling is_a('23', 'User'); will trigger __autoload() on "23". Previously, the above statement simply returned 'false'.
More info can be found here:
https://bugs.php.net/bug.php?id=55475
Whether this change is considered a bug and whether it will be reverted or kept in future versions is yet to be determined, but nevertheless it is how it is, for now...
up
18
p dot scheit at zweipol dot net
19 years ago
At least in PHP 5.1.6 this works as well with Interfaces.
<?php
interface test {
 public function A();
}
class TestImplementor implements test {
 public function A () {
 print "A";
 }
}
$testImpl = new TestImplementor();
var_dump(is_a($testImpl,'test'));
?>

will return true
up
11
cesoid at yahoo dot com
20 years ago
is_a returns TRUE for instances of children of the class.
For example:
class Animal
{}
class Dog extends Animal
{}
$test = new Dog();
In this example is_a($test, "Animal") would evaluate to TRUE as well as is_a($test, "Dog").
This seemed intuitive to me, but did not seem to be documented.
up
4
SlimDeluxe
3 years ago
For anyone wondering, this does not work with traits :(
up
2
dkrupyanskiy[at]gmail
8 years ago
Looks like the function signature given in description is wrong. Actually it can take a string as a first parameter in the case if $allow_string is set to true. 
It took some time to find out how the last parameter should be used. Please consider the following example
<?php
class Foo{}
spl_autoload_register(
 function($classname){
 printf('autoload has been triggered for %s%s', $classname, PHP_EOL);
 }
);
var_dump(is_a('UndefinedClassName', Foo::class, true));
?>
up
2
eitan at mosenkis dot net
14 years ago
As of PHP 5.3.9, is_a() seems to return false when passed a string for the first argument. Instead, use is_subclass_of() and, if necessary for your purposes, also check if the two arguments are equal, since is_subclass_of('foo', 'foo') will return false, while is_a('foo', 'foo') used to return true.
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