| 시간 제한 | 메모리 제한 | 제출 | 정답 | 맞힌 사람 | 정답 비율 |
|---|---|---|---|---|---|
| 2 초 | 2048 MB | 63 | 43 | 34 | 65.385% |
After another leak of personal data, the administrator of Pochta.com decided to tighten the rules for employee passwords. Now, each employee's password must consist of exactly $n$ characters, and non-letter characters must occur among every three consecutive characters. Additional restriction is that the non-letter character must be present in the center of the password: one center character if $n$ is odd, or both characters closest to the center if $n$ is even.
For example, for $n = 9,ドル the following passwords are valid: "p4ss\#or0s", "1a2b34CD5". The password "1234a56bc" is not valid because the fifth character must be non-letter. The password "9ASE\#orkd" is not valid because it contains three letters in a row.
For $n = 6,ドル the passwords "ab23bc" and "5a428E" are valid. The passwords "111e11" and "4sy1um" are not valid.
The employees now wonder: what is the minimum and maximum number of non-letter characters that can occur in a password of a given length? Help them figure this out.
The first line contains an integer $n$: the length of the password (1ドル \le n \le 1,000円,000円$).
Output two integers separated by a space: the minimum and maximum number of non-letter characters in the password.
1
1 1
2
2 2
3
1 3