| 시간 제한 | 메모리 제한 | 제출 | 정답 | 맞힌 사람 | 정답 비율 |
|---|---|---|---|---|---|
| 1 초 | 1024 MB | 58 | 19 | 19 | 33.929% |
Paimon just invents a new sorting algorithm which looks much like bubble sort, with a few differences. It accepts a 1ドル$-indexed sequence $A$ of length $n$ and sorts it. Its pseudo-code is shown below.
Functions 1 The Sorting Algorithm
If you don't believe this piece of algorithm can sort a sequence it will also be your task to prove it. Anyway here comes the question:
Given an integer sequence $A = a_1, a_2, \cdots, a_n$ of length $n,ドル for each of its prefix $A_k$ of length $k$ (that is, for each 1ドル \le k \le n,ドル consider the subsequence $A_k = a_1, a_2, \cdots, a_k$), count the number of swaps performed if we call $\text{SORT}(A_k)$.
There are multiple test cases. The first line of the input contains an integer $T$ indicating the number of test cases. For each test case:
The first line contains an integer $n$ (1ドル \le n \le 10^5$) indicating the length of the sequence.
The second line contains $n$ integers $a_1, a_2, \cdots, a_n$ (1ドル \le a_i \le n$) indicating the given sequence.
It's guaranteed that the sum of $n$ of all test cases will not exceed 10ドル^6$.
For each test case output one line containing $n$ integers $s_1, s_2, \cdots, s_n$ separated by a space, where $s_i$ is the number of swaps performed if we call $\text{SORT}(A_i)$.
3 5 2 3 2 1 5 3 1 2 3 1 1
0 2 3 5 7 0 2 4 0