30218번 - Weighted Window Sums 다국어

문제

Given a sequence of numbers, we define a window within the sequence to be a contiguous subsequence of those numbers. For example, in the sequence [3, 6, 2, 3, 5, 4], there are four windows of size 3: [3, 6, 2], [6, 2, 3], [2, 3, 5] and [3, 5, 4]. We call window i of size k the window which starts with the i^th value in the list and includes exactly k consecutive values, ending with the (i+k-1)^th value in the list.

For a window with values a₁, a₂, …, a_k, define its weighted window sum to be:

1a₁ + 2a₂ + 3a₃ + … + ka_k

For the four window sums described above, the corresponding weighted window sums are:

[3, 6, 2] → 1 × 3 + 2 × 6 + 3 × 2 = 21 (Rank 2)

[6, 2, 3] → 1 × 6 + 2 × 2 + 3 × 3 = 19 (Rank 1)

[2, 3, 5] → 1 × 2 + 2 × 3 + 3 × 5 = 23 (Rank 3)

[3, 5, 4] → 1 × 3 + 2 × 5 + 3 × 4 = 25 (Rank 4)

For each window of a given size within a sequence of numbers, we sort those windows in increasing order of weighted window sum, breaking ties by the starting index of the window, from smallest index to largest index.

Given a sequence of integers and the size of a window, sort each window of the given size in the sequence by weighted window sum in increasing order, breaking ties by the starting index of the window.

입력

The first input line contains two integers: n (1 ≤ n ≤ 2 × 10⁵) and k (1 ≤ k ≤ n), representing the length of the sequence and the size of the window. Each of the next n input lines will contain one number of the sequence, in order. Each of these values will be in between 1 and 10⁸, inclusive.

출력

Print a sorted list of the windows, with one window per line. For each window, output its starting index, followed by the weighted window sum of that window.

제한

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