25666번 - Just Another Number Theory Problem 다국어

문제

Given are $n$ prime numbers 1ドル < p_1 < p_2 < \ldots < p_n < 10^{18}$ with $p_1 \le 100$. We say that the number $x$ is good if $x$ is divisible by at least one $p_i$.

Take all good numbers $a_1, a_2, \cdots, a_m$ in $[0, p_1 \cdot p_2 \cdot \ldots \cdot p_n]$ and sort them in order ($a_1 < a_2 < \ldots < a_m$). Your task is to calculate $\sum_{i=1}^{m-1} (a_{i+1} - a_i)^2$. As the sum could be very large, you should output it modulo 998ドル,244円,353円$.

입력

The first line of the input contains a single integer $n$ (1ドル \le n \le 10^5$).

The next line of the input contains $n$ integers $p_1, p_2, \ldots, p_n$ (1ドル < p_1 < p_2 < \ldots < p_n < 10^{18}$). It is guaranteed that 2ドル \le p_1 < 100$ and each $p_i$ (1ドル \le i \le n$) is a prime number.

출력

Output a single line with a single integer, indicating the answer modulo 998ドル,244円,353円$.

제한

노트

In the first example, the list of good numbers is:

• $a_1 = 0$
• $a_2 = 2$
• $a_3 = 4$
• $a_4 = 5$
• $a_5 = 6$
• $a_6 = 8$
• $a_7 = 10$

Thus, the answer is $(2-0)^2+(4-2)^2+(5-4)^2+(6-5)^2+(8-6)^2+(10-8)^2=18$.