| 시간 제한 | 메모리 제한 | 제출 | 정답 | 맞힌 사람 | 정답 비율 |
|---|---|---|---|---|---|
| 서브태스크 참고 (추가 시간 없음) | 1024 MB | 161 | 57 | 47 | 39.167% |
You are given a string $S$ consisting of characters 0, 1, and ?. You can replace each ? with either 0 or 1. Your task is to find if it is possible to assign each ? to either 0 or 1 such that the resulting string has no substrings that are palindromes of length 5ドル$ or more.
The first line of the input gives the number of test cases, $T$. $T$ test cases follow.
Each test case consists of two lines.
The first line of each test case contains an integer $N,ドル denoting the length of the string $S$.
The second line of each test case contains a string $S$ of length $N$.
For each test case, output one line containing Case #x: y, where $x$ is the test case number (starting from 1) and $y$ is POSSIBLE if there is a possible resulting string that has no palindromic substrings of length 5ドル$ or more, or IMPOSSIBLE otherwise.
0, 1 and ?.시간 제한: 20 초
시간 제한: 90 초
2 9 100???001 5 100??
Case #1: IMPOSSIBLE Case #2: POSSIBLE
In Sample Case #1, to prevent the whole string from being a palindrome, the first and last question mark must be different characters.
If we replace first question mark with 0 and replace the last question mark with 1, we get 1000?1001. If the remaining ? is replaced by 1, we get 100011001, then the first 5ドル$ characters form a palindrome of length 5ドル$. Otherwise, we get 100001001, the first 6ドル$ characters are a palindrome of length 6ドル$.
If we replace first question mark with 1 we get 1001?0001. If the remaining ? is replaced by 1, we get 100110001, then the last 5ドル$ characters form a palindrome of length 5ドル$. Otherwise, we get 100100001, the last 6ドル$ characters are a palindrome of length 6ドル$.
Hence, there is no way to get a valid string.
In Sample Case #2, one of the valid strings after replacing all the ? is 10011.
Contest > Google > Kick Start > Google Kick Start 2022 > Round A C번