MacOsx - Shell - list all .php files and their octal permissions, inside a specifc folder

Question

is it possible to list all the ".php" files located into a direcotry and their octal permissions?

I would like to list them like this:

775 /folder/file.php
644 /folder/asd/file2.php
etc...

Answer 1

find /folder -name '*.php' -type f -print0 |
 perl -0 -lne 'printf "%o %s\n", (lstat $_)[2]&07777, $_'

See also this related question: Convert ls -l output format to chmod format.

-print0 is a GNU extension also supported by BSDs like OS/X. GNU find also has a -printf predicate which could display the mode, but that one has not been added to BSD's find.

^{(Tested on OS/X 10.8.4 and Debian 7 but should work on any system that has any version of perl and find -print0 which includes all GNU systems and all recent BSDs)}

• Filippo oretti: i launched this from iside my folder /htdocs but it doesn't works :( do you tryed by yourself?
• terdon: @sbaaaang did you replace /folder with the real path? If you run from inside the target folder, that will be ..

Answer 2

find /some/path -type f -name "*.php" -exec sh -c 'stat -f "%p %N" "{}" | sed -E s/^.{3}//' \;

This is tested on OS X 10.8.4. The sed pipe just cuts the first 3 characters off the output (filetype). Looks like OS X stat doesn't support straight-up octal permission output.

• Stéphane Chazelas: That assumes filenames don't contain double quote, backslash, dollar, backtick or newline characters and runs one sed, one sh and one stat commands per file.
• Mel Boyce: Yes, yes it does. I'm making the assumption that PHP files aren't likely to contain any of those characters.
• jsbillings: try stat -f "%OLp %N" file