compare a certain number of lines between columns of two files

Question

I have a thousand files and I need to verify if they all have exactly the same information in the second column up to a certain number of lines. Below an example. I would like to print the names of the files if the first 5 lines of the second columns of the files file1.txt and file2.txt were not equal. In this case the result should show: "difference between files file1.txt and file2.txt"

file1.txt

jose 50
maria 50
fernando 50
andres 50
martin 30
pablo 30
.
.
.

file2.txt

julia 50
julio 50
alan 50
ruth 50
ana 40
manuel 40
.
.
. 

• Nasir Riley: Are you only going to compare two at a time?
• user140259: No, I want to compare the files file2.txt, ..., file999.txt with the first (file1.txt)

Answer 1

Hmm. I think I would do a for loop through the files and compare then with comm.

/tmp ❯ comm -3 <(cat file1.txt|awk '{print 2ドル}') <(cat file2.txt|awk '{print 2ドル}') ⏎
30
30
 40
 40

Note the 30's and 40's are output from the files. Some basic usage of comm: comm -1 -3 <(sort -u FILE1.txt) <(sort -u FILE2.txt)

• -1 suppress lines unique to FILE1
• -2 suppress lines unique to FILE2
• -3 suppress lines that appear in both files

So to put all this together something like:

cd /path/to/files && find . -type f -name "*.txt" | while read filename
do
 echo "*** Checking $filename ***"; comm -3 <(cat reference.txt|awk '{print 2ドル}') <(cat $filename|awk '{print 2ドル}'); echo "";
done